要求在通用函数中实现Mul [英] Requiring implementation of Mul in generic function
问题描述
我试图在Rust中实现一个通用函数,其中对于参数的唯一要求是应该定义乘法操作。我试图实现一个通用的权力,但会用简单的立方体
函数来说明问题:
使用std :: ops :: Mul;
fn立方体< T:Mul>(x:T) - > T {
x * x * x
}
fn main(){
println!(5 ^ 3 = {},cube(5));
}
编译时出现这个错误:
error [E0369]:二元运算`*`不能用于< T as std :: ops :: Mul> ::输出`
- > src / main.rs:4:5
|
4 | x * x * x
| ^^^^^^^^^
|
=注意:< T as std :: ops :: Mul> :: Output`
这是什么意思?我选择了错误的特质吗?如何解决这个问题?
让我们分析一下您的示例:
fn cube< T:Mul>(x:T) - > T {
let a = x * x;
让b = a * x;
b
a的类型是什么
和 b
?在这种情况下, a
的类型是< T as std :: ops :: Mul> :: Output
- 听起来很熟悉错误信息?然后,我们再次尝试将该类型乘以 x
,但不能保证 Output
能够相乘我们做最简单的事情,并说
fn cube< T:Mul< Output = T>>( x:T) - > T {
x * x * x
}
不幸的是,错误:
$ b
error [E0382]:移动值的使用:`x`
- > src / lib.rs:6:9
|
6 | x * x * x
| - 移动
|后使用的^值|
|价值移到这里
|
= note:移动是因为`x`的类型为'T`,它没有实现`Copy`特性
这是因为 Mul
trait接受值的参数,所以我们添加 Copy
,以便我们可以复制这些值。
我也切换到,其中
子句我更喜欢它,并且使用这种内联很难操作:
fn cube< T>(x:T) - > T
其中
T:Mul<输出= T> +复制
{
x * x * x
}
I'm trying to implement a generic function in Rust where the only requirement for the argument is that the multiplication operation should be defined. I'm trying to implement a generic "power", but will go with a simpler cube
function to illustrate the problem:
use std::ops::Mul;
fn cube<T: Mul>(x: T) -> T {
x * x * x
}
fn main() {
println!("5^3 = {}", cube(5));
}
When compiling I get this error:
error[E0369]: binary operation `*` cannot be applied to type `<T as std::ops::Mul>::Output`
--> src/main.rs:4:5
|
4 | x * x * x
| ^^^^^^^^^
|
= note: an implementation of `std::ops::Mul` might be missing for `<T as std::ops::Mul>::Output`
What does this mean? Did I choose the wrong trait? How can I resolve this?
Let's break down your example a bit:
fn cube<T: Mul>(x: T) -> T {
let a = x * x;
let b = a * x;
b
}
What are the types of a
and b
? In this case, the type of a
is <T as std::ops::Mul>::Output
— sound familiar from the error message? Then, we are trying to multiply that type by x
again, but there's no guarantee that Output
is able to be multiplied by anything!
Let's do the simplest thing and say that T * T
needs to result in a T
:
fn cube<T: Mul<Output = T>>(x: T) -> T {
x * x * x
}
Unfortunately, this gives two similar errors:
error[E0382]: use of moved value: `x`
--> src/lib.rs:6:9
|
6 | x * x * x
| - ^ value used here after move
| |
| value moved here
|
= note: move occurs because `x` has type `T`, which does not implement the `Copy` trait
Which is because the Mul
trait takes arguments by value, so we add the Copy
so we can duplicate the values.
I also switched to the where
clause as I like it better and it is unwieldy to have that much inline:
fn cube<T>(x: T) -> T
where
T: Mul<Output = T> + Copy
{
x * x * x
}
这篇关于要求在通用函数中实现Mul的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!