将类型明确地放入钻石算子并让java找出它们之间有什么区别？ [英] Is there a difference between explicitly putting the type into the diamond operator vs letting java figure it out?

问题描述

  MyWrapper< String> wrapper = new MyWrapper< String>（）; 
  

vs initializing via：

  MyWrapper<字符串> wrapper = new MyWrapper<>（）; 
  

是否有任何理由为什么要使用前者而不使用后者？我看到很多前者;我不确定是否仅仅是因为那是人们习惯的，或者你有这样想写的原因。

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后者仅在Java 7以后才可用。这就是为什么你经常看到前者。后者是相同的，并且更短。

Is there any difference between initialization via:

MyWrapper<String> wrapper = new MyWrapper<String>();

vs initialization via:

MyWrapper<String> wrapper = new MyWrapper<>();

Is there any reason why one would want to use the former over the latter? I see a lot of the former; I'm not sure if it's just because that's what people are used to, or there's a reason you'd want to write it that way.

解决方案

The latter is only available since Java 7. That's why you often see the former. The latter is equivalent, and shorter.

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