如何在泛型中使用多个上界 [英] How to use multiple upper bounds in generics

问题描述

我有一个具有泛型类型的Interface Foo -

  public interface Foo< T> {
 boolean apply（T t）; 
 
 
 
 
 
 $ b 
有另一个实现这个接口的类Bar，但我想要的是泛型类型Bar应该是一个接口A和B类型的集合，用下面的定义给出编译器错误 -  
 
 
  public class Bar implements FOO<收集和LT ;?扩展A& B>> {
 @Override 
 public boolean apply（Collection< ;? extends A& B> collect）{
 ... 
} 
} 
  
您能否建议正确的方法来达到此目的？ 
 
 
我可以在方法级别使用多个边界吗？
解决方案
这不适用吗？
  public class Bar< T extends A& B个实现Foo< Collection< T>> {
 @Override 
 public boolean apply（Collection< T> collect）{
 ... 
} 
} 
  
 
I have a Interface Foo which has a generic type - 
 public interface Foo<T> {  
     boolean apply(T t);  
 }
Having another class Bar which implements this interface but what I want is the generic Type of Bar should be a Collection of type Interface A and B, With the below definition its giving compiler error - 
public class Bar implements Foo<Collection<? extends A & B>>{
  @Override
  public boolean apply(Collection<? extends A & B> collect){
   ...
  }  
}
Can you suggest the correct way to achieve this?


I can use multiple bounds at method level only?
解决方案
Wouldn't this work?
public class Bar<T extends A & B> implements Foo<Collection<T>>{
  @Override
  public boolean apply(Collection<T> collect){
   ...
  }  
}


                        
这篇关于如何在泛型中使用多个上界的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！