避免返回通配符类型 [英] Avoiding Returning Wildcard Types
问题描述
我有一个通配符类集合的类,它是一个单例类,如下所示:
public ObliviousClass {
private static final ObliviousClass INSTANCE = new ObliviousClass();
私人地图< Key,Type<>> map = new HashMap< Key,Type<>>();
public void putType(Key key,Type<> type){
map.put(type);
}
//返回单例
public static ObliviousClass getInstance(){
return INSTANCE;
}
}
我希望能够在客户端代码中为这个集合添加不同的参数化类型:
void clientMethod(){
ObliviousClass oc = ObliviousClass。的getInstance();
键入< Integer> intType = ...
键入< String> stringType = ...
oc.putType(new Key(0),intType);
oc.putType(new Key(1),stringType);
}
据我所知,一切正常。但是,客户还需要能够通过提供 Key
来获得 Type<?>
。因此,类似以下的方法将被添加到 ObliviousClass
:
public Type<?> getType(Key key){
return map.get(key);
}
但是,在我的方便副本 我了解这个问题,因为客户端必须将返回的 是否有更好的设计用于我正在尝试做的事情? 我四处搜寻,但无法找到完全清除的答案我的困惑。 以下是一种类型安全的方法,可将多个给定类型的实例存储在地图中。关键是您需要在检索值时提供 用法如下所示: I have a class with a collection of Wildcard Types that is a singleton, something like: I'd like to be able to add different Parameterized types to this collection in client code: Up to this point, as I understand it, everything is ok. But a client also needs to be able to get a But in my handy copy of Effective Java, I read: Do not use wildcard types as return types. I understand the issue, as the client would have to cast the returned Is there a better design for what I am trying to do?
-My current solution is to provide a static method for the client; something along the lines of: I searched around, but wasn't able to find an answer that totally cleared my confusion. Here's a type-safe way to store multiple instances of a given type in a map. The key is that you need to provide a Usage would look like this:
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的类型<?>
。但我真的不想让 ObliviousClass
一个泛型类型, ObliviousClass< T>
,因为那时我的客户端代码... b / b>
- 我目前的解决方案是为客户提供一种静态方法;以下内容:
public static< T> void getType(ObliviousClass instance,Key key,Type< T> dest){
dest =(Type< T>)instance.getType(key);
}
Class
实例来执行运行时类型检查,因为静态类型信息已被擦除。
class ObliviousClass {
private final Map< Key,Object> map = new HashMap< Key,Object>();
$ b $ public Object put(Key key,Object value)
{
return map.put(key,value);
}
public< T> T get(Key key,Class< ;? extends T> type)
{
return type.cast(map.get(key));
}
}
oc.put(k1,42);
oc.put(k2,Hello!);
...
Integer i = oc.get(k1,Integer.class);
String s = oc.get(k2,String.class);
Integer x = oc.get(k2,Integer.class); / *抛出ClassCastException * /
public ObliviousClass{
private static final ObliviousClass INSTANCE = new ObliviousClass();
private Map<Key, Type<?>> map = new HashMap<Key, Type<?>>();
public void putType(Key key, Type<?> type){
map.put(type);
}
// returns the singleton
public static ObliviousClass getInstance(){
return INSTANCE;
}
}
void clientMethod(){
ObliviousClass oc = ObliviousClass.getInstance();
Type<Integer> intType = ...
Type<String> stringType = ...
oc.putType(new Key(0), intType);
oc.putType(new Key(1), stringType);
}
Type<?>
provided the Key
. So a method something like the following would be added to ObliviousClass
:public Type<?> getType(Key key){
return map.get(key);
}
Type<?>
. But I really do not want to make ObliviousClass
a generic type, ObliviousClass<T>
, because then my client code above would not work... public static <T> void getType(ObliviousClass instance, Key key, Type<T> dest){
dest = (Type<T>)instance.getType(key);
}
Class
instance when retrieving values in order to perform runtime type-checking, because static type information has been erased.class ObliviousClass {
private final Map<Key, Object> map = new HashMap<Key, Object>();
public Object put(Key key, Object value)
{
return map.put(key, value);
}
public <T> T get(Key key, Class<? extends T> type)
{
return type.cast(map.get(key));
}
}
oc.put(k1, 42);
oc.put(k2, "Hello!");
...
Integer i = oc.get(k1, Integer.class);
String s = oc.get(k2, String.class);
Integer x = oc.get(k2, Integer.class); /* Throws ClassCastException */