表示3个值的最佳方式 [英] Best way to represent sets of 3 values

问题描述

假设我有100组3个值。第一个值是时间，第二个值是x位置，第三个值是y位置。例如，这将成为超​​过100秒的点的xy位置。
我有一个PHP背景。在PHP中，我会用像这样的3D关联数组来完成它：

  position [time] [x] [ y] 
  

所以我可以在某个时间访问x，y值。你会如何在C＃中做到这一点？我认为像名单和字典这样的泛型会这样做。但我不知道如何为3D数据集实现键值。 解决方案

它看起来像要访问在给定时间的x / y位置。您可能会考虑其他答案和字典的组合。

定义一个简单的结构体，其中包含x& y位置。

  public struct位置
 {
 public int X {get ; } 
 public int Y {get; } 
 
 public Position（int x，int y）
 {
 this.X = x; 
 this.Y = y; 
 
 
 
 
 
 
 $ b现在你可以将它们存储在字典中（可能） DateTime 作为键。
 字典<日期时间，位置> positions = new Dictionary< DateTime，Position>（）; 
 positions.Add（新的DateTime（2017,3,29,10,0,0），新的Position（10,10））; 
  
您可以像
  var pos = positions [new DateTime（2017,3,29,10,0,0）]; 
 Console.WriteLine（{0}：{1}，pos.X，pos.Y）; 
  
 
 
 
 
 
 
除此之外，例如，您将得到一个您希望查找的对象列表，然后您可以轻松地将它们转换为字典。说你得到这些列表（从其他答案）：
  public class PositionEntity 
 {
 public DateTime Time {get; set;} 
 public int X {get; set;} 
 public int Y {get; set;} 
} 
  
作为列表 entities ，您可以这样做：
  IEnumerable< PositionEntity>实体= ....从某处加载
 var dict = entities.ToDictionary（k => k.Time，v => new Position（v.X，v.Y））; 
  
 
Assume that I have 100 sets of 3 values. first value is time, second value is x position and 3rd value is y position. this is going to be the xy position of a point over 100 seconds for example.
I have a PHP background. in PHP I would do it with a 3D associative array like this :
position["time"]["x"]["y"]
so I can access x,y values at a certain time. How would you do this in c#? I think generics like list and dictionary would do that. but I don't know how to implement key values for a 3D set of data.
解决方案
It looks like you want to access an x/y position at a given time. You might consider a combination of the other answers along with a dictionary.

Define a simple struct which holds x & y positions. It is important that this object is immutable.
public struct Position
{
    public int X { get; }
    public int Y { get; }

    public Position(int x, int y)
    {
        this.X = x;
        this.Y = y;
    }
}
Now you can store these in a dictionary with (perhaps) DateTime as the key.
Dictionary<DateTime, Position> positions = new Dictionary<DateTime, Position>();
positions.Add(new DateTime(2017,3,29,10,0,0), new Position(10,10));
And you can read your position like
var pos = positions[new DateTime(2017,3,29,10,0,0)];
Console.WriteLine("{0}:{1}",pos.X,pos.Y);




A neat little addition to this is that if, for example, you are getting a list of these object you wish to lookup by time you can easily turn them into a dictionary. Say your get a list of these (from other answer):
public class PositionEntity
{
   public DateTime Time {get;set;}
   public int X {get;set;}
   public int Y {get;set;}
}
As a list entities you can do this:
IEnumerable<PositionEntity> entities = .... loaded from somewhere
var dict = entities.ToDictionary(k => k.Time, v => new Position(v.X,v.Y));


                        
这篇关于表示3个值的最佳方式的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！