Google地图API v3地理定位不适用于Google Chrome [英] Google Maps API v3 Geolocation not working in Google Chrome
问题描述
我使用Google Maps API v3地理位置来获取用户的实际位置。我从Google Developers发现了这篇文章：
https://developers.google.com/maps/documentation/javascript/examples/map-geolocation
这里我的代码（等于Google Maps示例代码）：
< head>
< script src =https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=true>< / script>
< script>
//注意：此示例要求您在浏览器提示
//时同意位置共享。如果您看到空白区域而不是地图，则此
//可能是因为您拒绝位置共享的权限。
var map;
函数initialize（）{
var mapOptions = {
zoom：6，
mapTypeId：google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map（document.getElementById（'map-canvas'），
mapOptions）;
//尝试HTML5地理定位
if（navigator.geolocation）{
navigator.geolocation.getCurrentPosition（function（position）{
var pos = new google.maps .LatLng（position.coords.latitude，
position.coords.longitude）;
var infowindow = new google.maps.InfoWindow（{
map：map，
位置：pos，
content：'使用HTML5找到的位置。'
}）;
map.setCenter（pos）;
}，function（）{
handleNoGeolocation（true）;
}）;
} else {
//浏览器不支持地理定位
handleNoGeolocation（false）;
函数handleNoGeolocation（errorFlag）{
if（errorFlag）{
var content ='错误：地理定位服务失败。
} else {
var content ='错误：您的浏览器不支持地理位置。
}
var options = {
map：map，
position：new google.maps.LatLng（60，105），
content：content
};
var infowindow = new google.maps.InfoWindow（options）;
map.setCenter（options.position）;
}
google.maps.event.addDomListener（window，'load'，initialize）;
< / script>
< / head>
< body>
< div id =container>
< div class =entry-content>
< div class =blogtitle> IT< / div>< p>& nbsp;< / p>< / td>< td> < / TD>< TD>< p为H.;&安培; NBSP;< / P>< / TD>< / TR>< / tbody的>< /表>< p为H.;&安培; NBSP; < / p为H.
< div id =map-canvas>< / div><！ - map-canvas end - >
< / div><！ - entry-content end - >
< / div><！ - container end - >
< / body>
这在Firefox中非常好，但在Google Chrome&苹果浏览器。我认为，因为Chrome& Safari是webkit浏览器。但是我不知道如何解决它。
有人可以帮我吗？
我找到了这个
看起来这是文件协议的安全限制。看起来你需要从服务器本地托管它。
我已经使用本地服务器测试了您的代码，只是工作正常。
希望我能帮上忙。
I'm using Google Maps API v3 Geolocation to get the users actual location. I found this post from Google Developers:
https://developers.google.com/maps/documentation/javascript/examples/map-geolocation
Here my code (equals to the code of Google Maps example):
<head>
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=true"></script>
<script>
// Note: This example requires that you consent to location sharing when
// prompted by your browser. If you see a blank space instead of the map, this
// is probably because you have denied permission for location sharing.
var map;
function initialize() {
var mapOptions = {
zoom: 6,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
map = new google.maps.Map(document.getElementById('map-canvas'),
mapOptions);
// Try HTML5 geolocation
if(navigator.geolocation) {
navigator.geolocation.getCurrentPosition(function(position) {
var pos = new google.maps.LatLng(position.coords.latitude,
position.coords.longitude);
var infowindow = new google.maps.InfoWindow({
map: map,
position: pos,
content: 'Location found using HTML5.'
});
map.setCenter(pos);
}, function() {
handleNoGeolocation(true);
});
} else {
// Browser doesn't support Geolocation
handleNoGeolocation(false);
}
}
function handleNoGeolocation(errorFlag) {
if (errorFlag) {
var content = 'Error: The Geolocation service failed.';
} else {
var content = 'Error: Your browser doesn\'t support geolocation.';
}
var options = {
map: map,
position: new google.maps.LatLng(60, 105),
content: content
};
var infowindow = new google.maps.InfoWindow(options);
map.setCenter(options.position);
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
</head>
<body>
<div id="container">
<div class="entry-content">
<div class="blogtitle">IT</div><p> </p></td><td> </td><td><p> </p></td></tr></tbody></table><p> </p>
<div id="map-canvas"></div><!-- map-canvas end -->
</div><!-- entry-content end -->
</div><!-- container end -->
</body>
This works quite fine in Firefox but not in Google Chrome & Safari. I think because Chrome & Safari are webkit browsers. But I don't know how to fix it.
Can someone please help me?
I have found this
It appears this is a security restriction for the file protocol. Looks like you are going to need to host it locally from a server.
I've tested your code with a local server and it just works fine. Hope I could help.
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