颠倒python中的星号三角形 [英] reverse upside down asterisk triangle in python
问题描述
我试图使用嵌套的for循环向用户询问一个整数,然后程序将输出一个倒置的倒置三角形,其基数有星号并正在下降。
应该看起来像这样:
*****
****
***
**
*
我的代码是:
def pattern():
integer = requestInteger(请输入数字)
在范围内(0,整数):
范围内的变量(整数,0,-1):
如果变量 - 1> ($'$')
sys.stdout.write('') )
输出:
*
**
***
****
*****
我不确定如何改变我的循环来完成这项工作,而且我一直在尝试一段时间,所以帮助会非常感谢。谢谢
我的采访就像这样:
<$ p
整数= int(raw_input(请输入一个数字))
为范围内的数字(0,整数):
打印*数字+**(整数 - 数字)
是必须的)?提示: *
运算符可轻松替换为 for
循环。
I am trying to use nested for loops to ask the user for an integer and then the program will output a reverse, upside down triangle, with the base of it having the number of asterisks and working its way down. It's supposed to look like this:
*****
****
***
**
*
The code I have:
def pattern():
integer = requestInteger("Please enter a number")
for number in range(0, integer):
for variable in range(integer, 0, -1):
if variable - 1 > number:
sys.stdout.write(' ')
else:
sys.stdout.write('*')
sys.stdout.write('\n')
Outputs this:
*
**
***
****
*****
I'm not really sure how to go about changing my for loops around to make this work, and I've been trying for a while, so help would be much appreciated. Thank you
My take would be something like this:
def pattern():
integer = int(raw_input("Please enter a number"))
for number in range(0, integer):
print " " * number + "*" * (integer - number)
Is this homework (nested loops are mandatory)? Hint: the *
operator can be easily replaced by a for
loop.
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