如何解析这个json数据到java [英] how to parse this json data to java
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问题描述
这里是json代码..我是json解析的新手..所以请让我知道如何将这个json数据解析为java。
在此先感谢!
{
几何体:{
location :{
lat:13.0561990,
lng:80.2348820
}
},
icon:http://maps.gstatic.com /mapfiles/place_api/icons/generic_business-71.png
标识: cf67cea9c203824f58eaf5abe98a08912593bf90,
名: Mahalingapuram分公司,
参考: CnRsAAAAlAu76wP4EspUn8qk6yUBndsDI7RaEmDaXHc2gP1bomAP_22ZeswWfj3ganEwX9jO2BYjRo6eoeKlwrSeMNDv5h94zqnsNncDntlKN_MqC-
类型:[建立],
附近:钦奈Nungambakkam Mahalingapuram大道
$ b $在这里解析java代码后发生错误
$ c> public static void main(String [] args)throws Exception {
InputStream is = JsonParsing.class.getResourceAsStream ();
String jsonTxt = IOUtils.toString(is);
JSONObject json =(JSONObject)JSONSerializer.toJSON(jsonTxt);
JSONObject html_attribution = json.getJSONObject(html_attribution);
JSONObject geometry = json.getJSONObject(geometry);
JSONObject location = json.getJSONObject(location);
double latitude = json.getDouble(latitude);
double longitude = json.getDouble(longitude);
String icon = result.getString(icon);
String id = result.getString(id);
String reference = result.getString(reference);
String name = result.getString(name);
String adjacent = result.getstring(vicinity);
System.out.println(html_attribution:+ html_attribution);
System.out.println(location: + location);
System.out.println(latitude:+ latitude);
System.out.println(latitude:+ longitude);
System.out.println( result:+ result);
}
解决方案
<我使用以下内容:
< a href =http://code.google.com/p/google-gson/ =nofollow> http://code.google.com/p/google-gson/
序列化为JSON:
Gson gson = new GsonBuilder()。create );
String jsonOutput = gson.toJson(someObject);
从JSON反序列化:
BagOfPrimitives obj = gson.fromJson(json,BagOfPrimitives.class);
用户指南可以在这里找到:
https://sites.google.com/site/gson/gson-user -guide
Here is the json code..i am new to json parsing..so please let me know how to parse this json data to java. thanks in advance!!
{
"geometry" : {
"location" : {
"lat" : 13.0561990,
"lng" : 80.2348820
}
},
"icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png",
"id" : "cf67cea9c203824f58eaf5abe98a08912593bf90",
"name" : "Mahalingapuram Branch",
"reference" : "CnRsAAAAlAu76wP4EspUn8qk6yUBndsDI7RaEmDaXHc2gP1bomAP_22ZeswWfj3ganEwX9jO2BYjRo6eoeKlwrSeMNDv5h94zqnsNncDntlKN_MqC-gegTBZLX5YxOSA-vzuk6bKe3BJlHytW_wKJJs0Nxf3jRIQT1yYWTlDdMhk9EyS8ulMghoUZK5J51RRVKo12LPdHm_qCQWX_VA",
"types" : [ "establishment" ],
"vicinity" : "Mahalingapuram Main Road, Nungambakkam, Chennai"
}
after parsing the java code here but error occur
public static void main(String[] args) throws Exception{
InputStream is = JsonParsing.class.getResourceAsStream( "");
String jsonTxt = IOUtils.toString( is );
JSONObject json = (JSONObject)JSONSerializer.toJSON(jsonTxt);
JSONObject html_attribution = json.getJSONObject("html_attribution");
JSONObject geometry= json.getJSONObject("geometry");
JSONObject location= json.getJSONObject("location");
double latitude = json.getDouble("latitude");
double longitude = json.getDouble("longitude");
String icon= result.getString("icon");
String id = result.getString("id");
String reference= result.getString("reference");
String name = result.getString("name");
String vicinity = result.getstring("vicinity");
System.out.println("html_attribution: " + html_attribution);
System.out.println("location: " + location);
System.out.println("latitude: " + latitude);
System.out.println("latitude: " + longitude);
System.out.println("result: " + result);
}
解决方案
I use the following:
http://code.google.com/p/google-gson/
Serialize to JSON:
Gson gson = new GsonBuilder().create();
String jsonOutput = gson.toJson(someObject);
De-serialize from JSON:
BagOfPrimitives obj = gson.fromJson(json, BagOfPrimitives.class);
A user guide can be found here:
https://sites.google.com/site/gson/gson-user-guide
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