HttpGet 401状态码，后跟200个状态码 [英] HttpGet 401 status code followed by 200 status code

问题描述

我有权访问服务器日志，当我尝试连接到服务器时并执行httpGet命令，我可以在日志中首先看到401状态（http Unauthorized），然后是200（http OK）。

2次尝试发生在httpClient.execute（httpGet）期间

以避免这种行为。任何想法？

以下是我目前使用的代码：

  HttpGet httpGet = new HttpGet（this.url + request）; 
 
 HttpParams httpParameters = new BasicHttpParams（）; 
 HttpConnectionParams.setConnectionTimeout（httpParameters，3000）; 
 HttpConnectionParams.setSoTimeout（httpParameters，5000）; 
 
 DefaultHttpClient httpClient = new DefaultHttpClient（httpParameters）; 
凭证creds =新的UsernamePasswordCredentials（登录名，密码）; 
 httpClient.getCredentialsProvider（）。setCredentials（new AuthScope（AuthScope.ANY_HOST，AuthScope.ANY_PORT），creds）; 
 
 HttpResponse响应= httpClient.execute（httpGet）; 
 int status = response.getStatusLine（）。getStatusCode（）; 
 Log.v（这是Response code status：+ status）; //代码状态= 200（即使401和200在服务器日志中可见）。 
  

有关信息，我使用的是Android应用程序的代码。

为了解决我的问题，我使用了一个与我的问题相关的另一个问题的答案（Adam Batkin）：使用Apache HttpClient 4进行抢先式基本身份验证（感谢Bret Okken提供的链接）。

我终于有了以下几行：

  httpGet.addHeader（BasicScheme.authenticate（creds，UTF8，假））; 
  

获得如下代码：

  HttpGet httpGet = new HttpGet（this.url + request）; 
 
 HttpParams httpParameters = new BasicHttpParams（）; 
 HttpConnectionParams.setConnectionTimeout（httpParameters，3000）; 
 HttpConnectionParams.setSoTimeout（httpParameters，5000）; 
 
 DefaultHttpClient httpClient = new DefaultHttpClient（httpParameters）; 
凭证creds =新的UsernamePasswordCredentials（登录名，密码）; 
 httpClient.getCredentialsProvider（）。setCredentials（new AuthScope（AuthScope.ANY_HOST，AuthScope.ANY_PORT），creds）; 
 
 httpGet.addHeader（BasicScheme.authenticate（creds，UTF8，false））; 
 
 HttpResponse响应= httpClient.execute（httpGet）; 
 int status = response.getStatusLine（）。getStatusCode（）; 
 Log.v（这是Response code status：+ status）; 
  

感谢Thomas Stets提供了有趣的答案。

I am facing a strange behaviour using the Apachage HttpComponent to access a webservice.

I have access to the server log and when I am trying to connect to the server and execute the httpGet command I can see in the log at first a 401 status (http Unauthorized) and then a 200 (http OK).

The 2 attempts take place during the "httpClient.execute(httpGet)"

So I am searching how to avoid this behaviour. Any ideas ?

Here is the following code I am currently using :

HttpGet httpGet = new HttpGet(this.url + request);

HttpParams httpParameters = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParameters,3000);
HttpConnectionParams.setSoTimeout(httpParameters,5000);

DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
Credentials creds = new UsernamePasswordCredentials(login, password);
httpClient.getCredentialsProvider().setCredentials(new AuthScope(AuthScope.ANY_HOST, AuthScope.ANY_PORT), creds);

HttpResponse response = httpClient.execute(httpGet);
int status = response.getStatusLine().getStatusCode();
Log.v(this, "Response code status: " + status); // code status = 200 (even if a 401 and then a 200 are visible in the server log).

For information, I am using this code for an Android application.

解决方案

To solve my problem, I used an answer (Adam Batkin) from another question related to my problem : Preemptive Basic authentication with Apache HttpClient 4 (Thanks Bret Okken for the link).

I finally had the following line :

httpGet.addHeader(BasicScheme.authenticate(creds, "UTF8", false));

To get a code like this :

HttpGet httpGet = new HttpGet(this.url + request);

HttpParams httpParameters = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParameters,3000);
HttpConnectionParams.setSoTimeout(httpParameters,5000);

DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
Credentials creds = new UsernamePasswordCredentials(login, password);
httpClient.getCredentialsProvider().setCredentials(new AuthScope(AuthScope.ANY_HOST, AuthScope.ANY_PORT), creds);

httpGet.addHeader(BasicScheme.authenticate(creds, "UTF8", false));

HttpResponse response = httpClient.execute(httpGet);
int status = response.getStatusLine().getStatusCode();
Log.v(this, "Response code status: " + status);

Thanks Thomas Stets for the interesting answer.

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