如何列出提交中的所有文件？ [英] How to list all the files in a commit?

问题描述

我正在寻找一个简单的 git 命令，它提供了一个格式良好的所有文件列表，这些文件是散列（SHA1）提交的一部分，没有多余

我试过了： $ b

尽管它列出了这些文件，但它还包含了各种不需要的差异信息。

是否有另外一个 git 命令会提供我想要的列表，这样我就可以避免从 git中解析它显示输出？

解决方案

首选方式 > plumbing 命令;应该是程序化的）：

  $ git diff-tree --no-commit-id --name-only -r bd61ad98 
 index.html 
 javascript / application.js 
 javascript / ie6.js 
  

另一种方式（脚本不太受欢迎，因为它是瓷器命令;这意味着面向用户）

  $ git show --pretty = - 仅限名称bd61ad98 
 index.html 
 javascript / application.js 
 javascript / ie6.js 
  

---

$ b

• - no-commit-id 取消提交ID输出。 b $ b
• - pretty 参数指定一个空的格式字符串以避免在开始处发生错误。


• - 仅限名称参数仅显示受影响的文件名（谢谢Hank）。
  
• - r 参数是递归到子树中

I am looking for a simple git command that provides a nicely formatted list of all files that were part of the commit given by a hash (SHA1), with no extraneous information.

I have tried:

git show a303aa90779efdd2f6b9d90693e2cbbbe4613c1d

Although it lists the files, it also includes unwanted diff information for each.

Is there another git command that will provide just the list I want, so that I can avoid parsing it from the git show output?

解决方案

Preferred Way (because it's a plumbing command; meant to be programmatic):

$ git diff-tree --no-commit-id --name-only -r bd61ad98
index.html
javascript/application.js
javascript/ie6.js

Another Way (less preferred for scripts, because it's a porcelain command; meant to be user-facing)

$ git show --pretty="" --name-only bd61ad98    
index.html
javascript/application.js
javascript/ie6.js

---

• The --no-commit-id suppresses the commit ID output.
• The --pretty argument specifies an empty format string to avoid the cruft at the beginning.
• The --name-only argument shows only the file names that were affected (Thanks Hank).
• The -r argument is to recurse into sub-trees

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