在Git中引用提交的孩子 [英] Referencing the child of a commit in Git

问题描述

如果您想将 HEAD 移至当前 HEAD 的父级，那很简单：

If you want to move the HEAD to the parent of the current HEAD, that's easy:

git reset --hard HEAD^

但是有什么简单的方法可以完成与此操作完全相反的操作，也就是将头部设置为当前头部的第一个子女提交？

But is there any simple way to do the exact opposite of this operation, that is, set the head to the current head's first child commit?

现在，我使用gitk作为解决方法（alt-tab，向上箭头，alt-tab，中键），但我想要一个更优雅的解决方案，也可以在gitk不可用时使用。 / b>

Right now, I use gitk as a workaround (alt-tab, up-arrow, alt-tab, middle-click), but I would like a more elegant solution, one that can also be used when gitk is not available.

推荐答案

#!/bin/bash

REV=$1

if [ x$REV == x ]; then
    echo "Usage: git-get-child  []"
    exit
fi

HASH=$(git-rev-parse $REV)

NUM=$2

if [ x$NUM == x ]; then
    NUM=1
fi

git rev-list --all --parents | grep " $HASH" | sed -n "${NUM}s/\([^ ]*\) .*$/\\1/p"

git rev-list --all --parents 完全符合我的需要：它迭代所有可访问的提交，并为每个提交以下行：

The git rev-list --all --parents does exactly what I need: it iterates over all reachable commits, and prints the following line for each:

SHA1_commit SHA1_parent1 SHA1_parent2 等。

grep表达式确保只有那些行被发现的地方是问题的SHA1是父级。然后我们得到第n个孩子的第n行，并得到孩子的SHA1。

The space in the grep expression ensures that only those lines are found where the SHA1 in question is a parent. Then we get the nth line for the nth child and get the child's SHA1.

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