Git - 使用filter-branch删除空变更集的提交 [英] Git - remove commits with empty changeset using filter-branch

问题描述

我如何使用git filter-branch删除没有变更集的提交？

我使用以下代码重写了我的git历史记录：

  git filter-branch --tree-filter'rm -r -f my_folder'-f HEAD 
  

这个解决方案效果很好，但现在我有很多提交空变更集的提交。我想删除这些提交。最好在msysgit。

重新分配不是真正的选择，因为我有超过4000个提交，其中一半必须被移除。

解决方案

只需在 - 修剪空白选项上添加：

git filter-branch --tree-filter'rm -rf my_folder'--prune-empty -f HEAD


（当然，如果你有其他的参考资料，你可能想用 - > all 而不是 HEAD 。）

请注意，这与 - 提交过滤;在这种情况下，查尔斯贝利有你的答案。

How do I remove commits which have no changeset using git filter-branch?

I rewrote my git history using:

git filter-branch --tree-filter 'rm -r -f my_folder' -f HEAD

this worked out well but now I have lots of commits with empty changesets. I would like to remove those commits. Preferably in msysgit.

Rebasing is not really an option because I have over 4000 commits and half of them must be removed.

解决方案

Just add on the --prune-empty option:

git filter-branch --tree-filter 'rm -rf my_folder' --prune-empty -f HEAD

(And of course, if you have other refs, you might want to rewrite everything with -- --all instead of just HEAD.)

Note that this isn't compatible with --commit-filter; in that case, Charles Bailey has your answer.

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