列表标签包含在一个分支 [英] list tags contained by a branch

问题描述

如何列出给定分支包含的标签，相反：

  git tag --contains< commit> ; 
  

其中只列出包含指定提交的代码。

如果像这样的东西不存在，我该如何测试一个提交是否被另一个提交包含，以便我可以编写脚本？

我可以这样做：

  commit = $（git rev-parse $ branch）$ b $ for $（git tag） 
做
 git log --pretty =％H $ tag | grep -q -E^ $ commit $
 done 
  

但我希望有一个更好的方法，因为这可能需要很长时间在一个存储库中有很多标签和提交。

你想：

  git log --simplify-by-decoration --decorate --pretty = oneline$ committish| fgrep'标签：'
  

但是，更常见的情况是找到最近的标签：

  git describe --tags --abbrev = 0$ committish
  

• - tags 将针对轻量级标签进行搜索，请不要使用if您只想考虑带注释的标签。
如果您还想看到通常的数字，请不要使用 - abbrev = 0 '提交最上面'和缩写哈希'后缀（例如v1.7.0-17-g7e5eb8）。

How can I list tags contained by a given branch, the opposite of:

git tag --contains <commit>

Which "only list tags which contain the specified commit".

If something like this does not exist, how do I test whether a commit is contained by another commit so that I can script this?

I could do this:

commit=$(git rev-parse $branch)
for tag in $(git tag)
do
    git log --pretty=%H $tag | grep -q -E "^$commit$"
done

But I hope there is a better way as this might take a long time in a repository with many tags and commits.

解决方案

This might be close to what you want:

git log --simplify-by-decoration --decorate --pretty=oneline "$committish" | fgrep 'tag: '

But, the more common situation is to just find the most recent tag:

git describe --tags --abbrev=0 "$committish"

• --tags will search against lightweight tags, do not use it if you only want to consider annotated tags.
• Do not use --abbrev=0 if you want to also see the usual "number of ‘commits on top’ and abbreviated hash" suffix (e.g. v1.7.0-17-g7e5eb8).

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