我可以让git diff只显示更改的文件名和行号吗？ [英] Can I make git diff only show the changed file names and line numbers?

问题描述

基本上，我不想看到更改的内容，只是文件名和行号。

：如果您只是寻找已更改文件的名称（，而不是已更改行的行号），则这很容易，点击此链接到另一个答案。

---

这里没有内置选项（我认为它也不是那么有用），但是它可以在git中执行此操作，在一个外部差异脚本。

这是一个非常糟糕的;这将取决于你如何修改你想要的输出。

 ＃！ / bin / sh 
＃
＃运行以下命令：
＃GIT_EXTERNAL_DIFF =< script of name> git diff ... 
＃
 case $＃
 1）unmerged file $ @，无法显示行号; 1号出口;; 
 7）;; 
 *）echo我不知道该怎么做，帮忙！; 1号出口;; 
 esac 
 
 path = $ 1 
 old_file = $ 2 
 old_hex = $ 3 
 old_mode = $ 4 
 new_file = $ 5 
 new_hex = $ 6 
 new_mode = $ 7 
 
 printf'％s：'$ path 
 diff $ old_file $ new_file | grep -v'^ [<>]'
  

有关外部差异的详细信息，请参阅在 git手册页面< GIT_EXTERNAL_DIFF / a>（在700行左右，非常接近结尾）。

Basically, I don't want to see the changed content, just the file names and line numbers.

解决方案

Note: if you're just looking for the names of changed files (without the line numbers for lines that were changed), that's easy, click this link to another answer here.

---

There's no built-in option for this (and I don't think it's all that useful either), but it is possible to do this in git, with the help of an "external diff" script.

Here's a pretty crappy one; it will be up to you to fix up the output the way you would like it.

#! /bin/sh
#
# run this with:
#    GIT_EXTERNAL_DIFF=<name of script> git diff ...
#
case $# in
1) "unmerged file $@, can't show you line numbers"; exit 1;;
7) ;;
*) echo "I don't know what to do, help!"; exit 1;;
esac

path=$1
old_file=$2
old_hex=$3
old_mode=$4
new_file=$5
new_hex=$6
new_mode=$7

printf '%s: ' $path
diff $old_file $new_file | grep -v '^[<>-]'

For details on "external diff" see the description of GIT_EXTERNAL_DIFF in the git manual page (around line 700, pretty close to the end).

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