列表提交不触及特定路径 [英] List commits not touching specific paths
问题描述
我需要列出在源代码树中碰到一个路径的提交。
C触摸 foo 和 bar
触摸 foo / p> A - 基线
在A和DI之间需要一个所有提交文件的列表 foo < b $ b 我尝试了 请指教。 git rev-list A..D --exclude ='bar' - foo
但这给了我B和C两者。 / p>
comm
命令。只需获取影响感兴趣文件的所有提交列表,以及影响提交不感兴趣的文件的所有提交列表,然后使用 comm
来提取感兴趣的项目(那些出现在第一个列表中,但不在第一个和第二个列表中的)。
因此:
git rev-list A..D - foo> / tmp / list1
git rev-list A..D - bar> / tmp / list2
comm -23 / tmp / list [12]
请注意,对于 comm
的排序要求是故意违反的(这里违反了);如果您的特定 comm
坚持,您可能需要编写自己的变体。
编辑:我在Git 2.8.1中测试了VonC的建议,通过使用文件A / a和B / b的初始提交来创建一个新的存储库:
$ git --version
git版本2.8.1
$ git log --oneline --name-status
731a059 both
MA / a
MB / b
6894130 B仅
MB / b
b4bb2d8 A仅
MA / a
f134515初始
AA / a
AB / b
添加 - A
正确地丢弃
B commit:
$ git log --oneline --name-status - A
731a059均为
MA / a
b4bb2d8 A仅
MA / a
f134515初始
AA / a
但是,加入 :(排除):B
对所选提交没有任何影响:
$ git log --oneline --name-status - A':(不包括):B'
731a059均为
MA / a
b4bb2d8 A仅
MA / a
f134515初始
AA / a
提交 731a059
,触碰文件A / a和B / b仍然出现在输出中,就像初始提交 f134515
一样。不同之处在于,当选择了也影响B / b的两个提交时,文件 B / b被省略。原始问题要求排除整个提交。
编辑2(使用 comm
和bash的<(...)
语法,以省略临时文件):
$ b pre $
[〜/ tmp / git-exclude] $ comm -23< HEAD - B)
b4bb2d84d633e2254081b7ce99681d92b7974a9d
这是所需的输出,因为只提交 b4bb2
仅影响 A
目录。
I need to list commits that touch one path in the source tree but not another.
D - head
C - touched foo and bar
B - touched foo
A - baseline
Between A and D I want a list of all commits touching folder foo unless they also touch folder bar, in other words, in the example above I would expect to see B but not C.
I tried git rev-list A..D --exclude='bar' -- foo
but that gives me both B and C still.
Please advise.
There is nothing built into Git to do this. However, it's easy to construct with a small shell script using the comm
command. Simply get a list of all commits that affect interesting files, and a second list of all commits that affect files that make the commit uninteresting, then use comm
to extract the interesting items (those that appear in the first list, but not in both the first and second list).
Hence:
git rev-list A..D -- foo > /tmp/list1
git rev-list A..D -- bar > /tmp/list2
comm -23 /tmp/list[12]
Note that the "sorted" requirement for comm
is deliberately violate-able (and is violated here); if your particular comm
insists on it, you may need to write your own variation.
Edit: I tested VonC's suggestion, in Git 2.8.1, by making a new repository with an initial commit with files A/a and B/b:
$ git --version
git version 2.8.1
$ git log --oneline --name-status
731a059 both
M A/a
M B/b
6894130 B only
M B/b
b4bb2d8 A only
M A/a
f134515 initial
A A/a
A B/b
Adding -- A
correctly discards the B only
commit:
$ git log --oneline --name-status -- A
731a059 both
M A/a
b4bb2d8 A only
M A/a
f134515 initial
A A/a
However, adding :(exclude):B
has no effect on the selected commits:
$ git log --oneline --name-status -- A ':(exclude):B'
731a059 both
M A/a
b4bb2d8 A only
M A/a
f134515 initial
A A/a
Commit 731a059
, which touches files A/a and B/b, still appears in the output, as does initial commit f134515
. The difference is that when the two commits that also affect B/b are selected, the file B/b is omitted. The original question calls for the entire commit to be excluded.
Edit 2 (using comm
and bash's <(...)
syntax, to omit the temp files):
[~/tmp/git-exclude]$ comm -23 <(git rev-list HEAD -- A) <(git rev-list HEAD -- B)
b4bb2d84d633e2254081b7ce99681d92b7974a9d
This is the desired output, since only commit b4bb2
affects only the A
directory.
这篇关于列表提交不触及特定路径的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!