Markdown / Github：将代码块的语法突出显示为列表的子代 [英] Markdown/Github: syntax highlighting of code block as a child of a list

问题描述

在Github / MD中，如果我们希望在代码块是列表子时启用它，我们需要以8个空格来表示它。

但是如何使该代码块具有语法高亮功能？

以下代码无法按预期运行......

  1. foo 
 
```python 
 print'bar'
```
 
 2. bar 
  

解决方案

 ```python 
 print'bar '
```
  

without spaces should work：from GitHub帮助页面：

<只需将代码块封装在```和中，您就不需要手动缩进来触发代码块。

---

如 hilz 的 answer ，你需要缩进````缩进级别+ 2空格，而不是你的列表。

c的内容ode块不需要缩进。

  1。 foo 
 
````python 
 print'bar'
```
 
 1. 
 
`` ``python 
 print'bar'
````
  

a href =https://gist.github.com/VonC/10666727 =nofollow noreferrer>以此为例：

In Github/MD, if we want to enable code block when it is a child of list, we need to intent it by 8 spaces.

But how to make that code block has the syntax highlighting feature?

The following code does not work as expected...

    1. foo

             ```python
                print 'bar'
             ```

    2. bar

解决方案

```python
print 'bar'
```

without spaces should work: from GitHub help page:

Just wrap your code blocks in ``` and you won't need to indent manually to trigger a code block.

---

As illustrated in hilz's answer below, you need to indent the ```` with the same indentation level + 2 spaces than your list.
The content of the code block doesn't need to be indented.

1. foo

  ````python
print 'bar'
  ````

  1.

    ````python
print 'bar'
    ````

See this gist as an example:

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