无法打开ServletContext资源 [英] Could not open ServletContext resource

问题描述

我有一个WAR包。

$这个问题与一个较老的问题非常类似，但解决方案对我无效。 b $ b

在 web.xml中

 <上下文-param> 
< param-name> contextConfigLocation< / param-name> 
< param-value> classpath：application-context.xml< / param-value> 
< / context-param> 
 
< listener> 
< listener-class> 
 org.springframework.web.context.ContextLoaderListener 
< / listener-class> 
< / listener> 
  

在 application-context.xml

 < bean id =placeholderConfigclass =org.springframework.beans.factory.config.PropertyPlaceholderConfigurer> 
< property name =location> 
< value> classpath：social.properties< / value> 
< / property> 
< / bean> 
  

但是得到这个：

org.springframework.beans.factory.BeanInitializationException：无法加载属性;嵌套的异常是java.io.FileNotFoundException：无法打开ServletContext资源[/social.properties]

我检查了WAR包 - code> .xml 和 .properties 文件都位于 / WEB-INF / classes $ b

.properties 文件位于 src / main / resources src / main / java （在默认的包中）和maven传输它们（c $ c>和 .xml 我认为）正确地在 WEB-INF / classes

的默认包中有没有人知道为什么我可以得到这个例外？谢谢。

编辑：我只是想补充JUnit测试正确（我的意思是他们加载他们应该从 social.properties ），但运行应用程序时忽略了我的 classpath：前缀


解决方案 div>

不要使用classpath。这可能会导致不同ClassLoaders（容器与应用程序）的问题。 WEB-INF总是最好的选择。

 < context-param> 
< param-name> contextConfigLocation< / param-name> 
< param-value> /WEB-INF/spring-config.xml< / param-value> 
< / context-param> 
  

和

 < bean id =placeholderConfigclass =org.springframework.beans.factory.config.PropertyPlaceholderConfigurer> 
< property name =location> 
<值> /WEB-INF/social.properties< /值> 
< / property> 
< / bean> 
  

This is quite similar question to one older but the solution did not work for me.

I have a WAR package.

In web.xml

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:application-context.xml</param-value>
</context-param>

<listener>
    <listener-class>
        org.springframework.web.context.ContextLoaderListener
    </listener-class>
</listener>

In application-context.xml

<bean id="placeholderConfig" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
    <property name="location">
        <value>classpath:social.properties</value>
    </property>
</bean>

But getting this:

org.springframework.beans.factory.BeanInitializationException: Could not load properties; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/social.properties]

I checked the WAR package - .xml and .properties files are both in /WEB-INF/classes

.properties file is in src/main/resources and .xml in src/main/java (in default package both) and maven transports them (I think) correctly in the default package of WEB-INF/classes

Does anyone know why i could get this exception? Thank you.

EDIT: I just want to add that JUnit tests goes correctly (i mean they load what they should from social.properties) but when running the app it ignores my classpath: prefix

解决方案

Do not use classpath. This may cause problems with different ClassLoaders (container vs. application). WEB-INF is always the better choice.

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring-config.xml</param-value>
</context-param>

and

<bean id="placeholderConfig" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
     <property name="location">
         <value>/WEB-INF/social.properties</value>
     </property>
</bean>

这篇关于无法打开ServletContext资源的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！