与glassfish和春天的URL映射 [英] URL mapping with glassfish and spring

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问题描述

我正在为glassfish 2.1创建一个hello world spring项目。我正在尝试使用SimpleUrlHandlerMapping将以/spring/*.htm结尾的所有内容映射到我的弹簧控制器。这里是我的:

web.xml:

 < ;?xml version =1.0encoding =ISO-8859-1?> 
< web-app xmlns =http://java.sun.com/xml/ns/j2ee
xmlns:xsi =http://www.w3.org/2001/XMLSchema -instance
XSI:的schemaLocation = http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd
version =2.4>
< display-name>测试MVC项目< /显示名称>

< servlet>
< servlet-name>调度程序< / servlet-name>
< servlet-class>
org.springframework.web.servlet.DispatcherServlet
< / servlet-class>
<加载启动> 1< /加载启动>
< / servlet>

< servlet-mapping>
< servlet-name>调度程序< / servlet-name>
< url-pattern> / spring / *< / url-pattern>
< / servlet-mapping>

< welcome-file-list>
< welcome-file> index.html< / welcome-file>
< / welcome-file-list>
< / web-app>

在我的dispatcher-servlet.xml文件中:

 < beans xmlns =http://www.springframework.org/schema/beans
xmlns:xsi =http://www.w3.org / 2001 / XMLSchema-instance
xsi:schemaLocation =http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans -2.5.xsd>

< bean id =defaultController
class =org.springframework.web.servlet.mvc.ParameterizableViewController>
< property name =viewNamevalue =WEB-INF / jsp / springbean-view.jsp/>
< / bean>

< bean id =urlMapping
class =org.springframework.web.servlet.handler.SimpleUrlHandlerMapping>
< property name =mappings>
<道具>
< prop key =*。htm> defaultController< / prop>
< /道具>
< / property>
< / bean>

< / beans>

我的sun-web.xml文件:

 <太阳web应用程序> 
< context-root> / foo< / context-root>
< class-loader delegate =false/>
< / sun-web-app>

当我请求 http:// localhost:9680 / foo ,我看到欢迎页面。当我请求 http:// localhost:9680 / foo / spring / test.htm 时,我得到了一个404。



我在servlet.xml文件的urlMapping中尝试了许多模式变体。我得到的唯一工作是如果我这样做:

 < bean id =urlMapping
类= org.springframework.web.servlet.handler.SimpleUrlHandlerMapping >
< property name =mappings>
<道具>
< prop key =/ *> defaultController< / prop>
< /道具>
< / property>
< / bean>

当我请求 http:// localhost:9680 / foo / spring ,它的工作原理。对我来说,这意味着我的web.xml是正确的,因为它正确地将请求传递给调度servlet。当我请求 http:// localhost:9680 / foo / spring / test.htm (或任何在/春/ *结束时,我得到一个500与此异常:




javax.servlet.ServletException:PWC1232:超过最大深度嵌套的请求调度:20


我觉得我在做一些非常愚蠢的事情,但经过几个小时的谷歌搜索和玩耍与映射,我很难过。

解决方案



 < prop key =/ *> defaultController< / prop> 

但是,这可以更简单:

 < bean id =urlMappingclass = org.springframework.web.servlet.handler.SimpleUrlHandlerMapping > 
将属性名= 的DefaultHandler REF = defaultController/>
将/豆腐>

另外,原因哟你会得到无尽的转发循环:

 < bean id =defaultControllerclass =org.springframework。 web.servlet.mvc.ParameterizableViewController> 
< property name =viewNamevalue =WEB-INF / jsp / springbean-view.jsp/>
< / bean>

这里的问题是没有前置 / viewName 上,所以它被解释为相对的。因此,当您转到以 /foo/spring/test.htm 结尾的URL时,相对的转发URI是 / foo / spring / WEB-INF /jsp/springbean-view.jsp ,后者又被 web.xml中的 url-pattern / code>,所以它会回到 DispatcherServlet ,它会转发它等等等等。无尽的循环。



$ p
$ b

 < property name =viewNamevalue =/ WEB-INF / jsp / springbean-view.jsp/> 

请注意前面的 /


I'm creating a hello world spring project on glassfish 2.1. I'm trying to use the SimpleUrlHandlerMapping to map everything that ends in /spring/*.htm to my spring controller. Here is what I have:

web.xml:

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
    <display-name>Test MVC Project</display-name>

    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

  <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/spring/*</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
    </welcome-file-list> 
</web-app>

in my dispatcher-servlet.xml file:

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

    <bean id="defaultController"
        class="org.springframework.web.servlet.mvc.ParameterizableViewController">
        <property name="viewName" value="WEB-INF/jsp/springbean-view.jsp" />
    </bean>

    <bean id="urlMapping"
        class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="*.htm">defaultController</prop>
            </props>
        </property>
    </bean>

</beans>

My sun-web.xml file:

<sun-web-app>
    <context-root>/foo</context-root>
    <class-loader delegate="false" />
</sun-web-app>

When I request http://localhost:9680/foo, I see the welcome page. When I request http://localhost:9680/foo/spring/test.htm, I get a 404.

I have tried many variations of patterns in the urlMapping in the servlet.xml file. The only thing I have gotten to work is if I do this:

<bean id="urlMapping"
    class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
    <property name="mappings">
        <props>
            <prop key="/*">defaultController</prop>
        </props>
    </property>
</bean>

When I request http://localhost:9680/foo/spring, it works. To me, this means that my web.xml is correct because it is properly passing the request to the dispatch servlet. When I request http://localhost:9680/foo/spring/test.htm (or anything that ends in /spring/*, I get a 500 with this exception:

javax.servlet.ServletException: PWC1232: Exceeded maximum depth for nested request dispatches: 20

I feel like I'm doing something very stupid, but after several hours of googling and playing around with the mappings, I'm stumped.

解决方案

This is almost correct:

<prop key="/*">defaultController</prop>

But that can be simpler still:

<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
    <property name="defaultHandler" ref="defaultController"/>
</bean>

Also, the reason you're getting the endless forwarding loop is this:

<bean id="defaultController" class="org.springframework.web.servlet.mvc.ParameterizableViewController">
    <property name="viewName" value="WEB-INF/jsp/springbean-view.jsp" />
</bean>

The problem here is there's no leading / on the viewName, so it's interpreted as relative. So, when you go to the URL ending /foo/spring/test.htm, the relative forward URI is /foo/spring/WEB-INF/jsp/springbean-view.jsp, which in turn is caught by the url-pattern in web.xml, so it goers back into the DispatcherServlet, which forwards it on, etc etc etc. Endless loop.

Easy fix:

<property name="viewName" value="/WEB-INF/jsp/springbean-view.jsp" />

Note the leading /

这篇关于与glassfish和春天的URL映射的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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