调用带有base64编码的gmail发送API时，ByteString错误的值无效<或> [英] Invalid value for ByteString error when calling gmail send API with base64 encoded < or >

问题描述

真的停留在这张照片上，把我的头发拉出来试图弄清楚该做什么，到处寻找并尝试了一切，但仍然卡住了。任何帮助都非常感谢。

因此，我打电话给Gmail发送邮件API：

https://www.googleapis.com/gmail/v1/users/me/messages/send

我通过在编码的原始消息下面BASE64：

VG86IGVjaG9zaWduLnNmZGMucWFAZ21haWwuY29tDQpTdWJqZWN0OiBSZTogd2UgaGF2ZSBhIGNvb2wgcHJvZHVjdA0KSW4tUmVwbHktVG86IDxDQUFMRnBBSmc1aTJlQ1p4T2dQWlhUdnNaN0J5M0gzNlRCMkNQYTdoVEtzTXh2bXZfT3dAbWFpbC5nbWFpbC5jb20 + DQpSZWZlcmVuY2VzOiA8Q0FBTEZwQUpnNWkyZUNaeE9nUFpYVHZzWjdCeTNIMzZUQjJDUGE3aFRLc014dm12X093QG1haWwuZ21haWwuY29tPg0KDQoxMTozNg = =

解码为：

 收件人：[e-mail] 
主题：Re：我们有一个很酷的产品
 In-Reply-To：< [e-mail]> 
参考文献：< [e-mail]> 
 
 11:36 
  

我得到这个错误：

状态码：400和状态：错误的请求和响应：{error：{errors：[{domain：global，原因：invalid，message：ByteString的值无效

问题是小于< / code>大于< code>> In-Reply-To和References标头中的符号，因为我想要我尝试省略< 和> ，但回复然后不线程。

谢谢 如果您正在使用PHP试试这个（否则试着把它转换成你使用的任何语言）

在将mime消息设置为raw属性之前调用下面的函数。

 私有函数base64url_encode（$ mime）{
 return rtrim（str tr（base64_encode（$ mime），'+ /'，'-_'），'='）; 
} 
  

Really stuck on this one and pulling my hair out trying to figure out what to do, searched everywhere and tried everything but still stuck. Any help is much appreciated.

So I am calling the Gmail send message API:

https://www.googleapis.com/gmail/v1/users/me/messages/send

I pass in the following base64 encoded raw message:

VG86IGVjaG9zaWduLnNmZGMucWFAZ21haWwuY29tDQpTdWJqZWN0OiBSZTogd2UgaGF2ZSBhIGNvb2wgcHJvZHVjdA0KSW4tUmVwbHktVG86IDxDQUFMRnBBSmc1aTJlQ1p4T2dQWlhUdnNaN0J5M0gzNlRCMkNQYTdoVEtzTXh2bXZfT3dAbWFpbC5nbWFpbC5jb20+DQpSZWZlcmVuY2VzOiA8Q0FBTEZwQUpnNWkyZUNaeE9nUFpYVHZzWjdCeTNIMzZUQjJDUGE3aFRLc014dm12X093QG1haWwuZ21haWwuY29tPg0KDQoxMTozNg==

Which decodes to:

To: [e-mail]
Subject: Re: we have a cool product
In-Reply-To: <[e-mail]>
References: <[e-mail]>

11:36

I get the error:

Status code: 400 and status: Bad Request and response: { "error": { "errors": [ { "domain": "global", "reason": "invalid", "message": "Invalid value for ByteString

The problem is the less than < and greater than > symbols in the In-Reply-To and References headers. I need those headers because I am trying to have the email come as a reply on the thread. I tried to leave out the < and > but the reply then does not thread.

Thanks

解决方案

If you are using PHP try this (otherwise try converting it to whatever language you are using)

Call the below function on your mime message before setting it to the raw property.

private function base64url_encode($mime) {
    return rtrim(strtr(base64_encode($mime), '+/', '-_'), '=');
}

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