SMTP将邮件发送给许多收件人，但没有收到它 [英] SMTP sent mail to many recipients but doesn't received it
问题描述
我写了一个Python脚本来自动发送一些信息给我的朋友。我使用SMTPlib，如果我只发送给我或另外添加另一封邮件，它会很好用。
当我尝试通过脚本发送至17封电子邮件（包括发件人电子邮件）时，我检查了基于Gmail的已发邮件，发现邮件已发送但我没有收到它。 只有第一个接受者收到该邮件。
如果我通过该邮件回复所有人，每个人都只收到该回复。
我不知道为什么他们没有收到它，当我从脚本发送时，我问我的朋友检查垃圾邮件，但她没有找到任何东西。
这是我的代码：
＃！/ usr / bin / env python
导入smtplib
从datetime导入csv
导入日期时间，timedelta
SMTP_SERVER ='smtp.gmail.com'
SMTP_PORT = 587
sender ='MYBOT@gmail.com'
密码=无
开放（'pass'，'rt'）为f：
password = f。阅读（）。strip（'\\\
'）
def send_mail（收件人，主题，正文）：
发送愉快的bithday邮件
headers = [From：+ sender，
Subject：+ subject，
To：+ recipient，
MIME-Version ：1.0，
Content-Type：text / html]
headers =\r\\\
.join（headers）
smtp = smtplib.SMTP（SMTP_SERVER，SMTP_PORT）
smtp.ehlo（）
smtp.starttls（）
smtp.ehlo
smtp.login（发件人，密码）
body =+ body +
smtp.sendmail（发件人，收件人，标题+\r\\\
\r\\\
+正文）
打印发送至，
打印收件人
smtp.quit（）
def send_happybirthday（收件人）：
body =祝你生日快乐！
\\\
< br />从C2k8pro与爱
subject ='[BirthReminder]祝你生日快乐！来自C2k8pro'
send_mail（收件人，主题，body）
def send_notification（all_mails，names）：
body =明天是％s的生日％names
send_mail（all_mails ，body，body）
def test_send_mail（）：
notify_body =明天是
recipients = ['MYBOT @ gmail。 com']
today = datetime.now（）
format =％d-％m-％Y
今天打印
today_in_str = datetime.strftime（今天，格式）
def read_csv（）：
FILENAME ='mails.csv'
reader = csv.reader（open（FILENAME，'rt'） ，'delimiter ='，'）
today = datetime.now（）
one_day = timedelta（days = 1）
明天=今天+ one_day
all_mails = []
str_format =％d /％m
str_today = today.strftime（str_format ）
str_tomorrow = tomorrow.strftime（str_format）
print'今天是'，str_today
tomorrow_birth = []
阅读器中的行：
name = row [1] .strip（）
dob = row [2]
dmy = dob.split（/）
mail = row [3]
all_mails.append （邮件）
#TODO修复只有1位数字的dob
birth_date = dmy [0] +/+ dmy [1]
如果str_today == birth_date：
print'生日快乐％s'％姓名
尝试：
send_happybirthday（邮件）
除了例外，e：
print e
elif str_tomorrow == birth_date：
tomorrow_birth.append（name）
print明天是％s的生日％name
＃删除空字符串
all_mails = filter（None，all_mails）
print'All mail：'，len（all_mails）
str_all_mails ='，'.join（all_mails）
if tomorrow_birth：
all_tomorrow ='，'.join（tomorrow_birth）
send_notification（str_all_mails，all_tomorrow）
def main（）：
read_csv（）
if __name__ ==__main__：
main（）
任何人都可以解释这一点。
我从这里找到了解决方案
用Python发送电子邮件给.txt文件中的多个收件人smtplib
我传递了一个字符串，其中包含所有以逗号分隔的收件人，分别是msg ['To']和sendmail（）。
对msg ['To']是真的，但对于sendmail，我必须使用一个列表。
I 've written a Python script to automatically send some information to my friends. I used SMTPlib, it works well if I only sent to me or addition another mail .
When i try to send to 17 emails (including my sender email) through script, then I checked sent mail on web-base Gmail, i saw that mail was sent but I didn't receive it. ONLY FIRST RECIPIENT received that mail. If I reply to all from that mail, everyone got only that reply.
I cant figure out why they didn‘t received it when I sent from script, I ask my friend check in spam but she didn't find anything.
This is my code:
#!/usr/bin/env python
import smtplib
import csv
from datetime import datetime, timedelta
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'MYBOT@gmail.com'
password = None
with open('pass', 'rt') as f:
password = f.read().strip('\n')
def send_mail(recipient, subject, body):
"""
Send happy bithday mail
"""
headers = ["From: " + sender,
"Subject: " + subject,
"To: " + recipient,
"MIME-Version: 1.0",
"Content-Type: text/html"]
headers = "\r\n".join(headers)
smtp = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
smtp.ehlo()
smtp.starttls()
smtp.ehlo
smtp.login(sender, password)
body = "" + body +""
smtp.sendmail(sender, recipient, headers + "\r\n\r\n" + body)
print "Sent to ",
print recipient
smtp.quit()
def send_happybirthday(recipient):
body = """Happy birthday to you!
\n<br/>From C2k8pro with love
"""
subject ='[BirthReminder] Happy birthday to you! from C2k8pro'
send_mail(recipient, subject, body)
def send_notification(all_mails, names):
body = """Tomorrow is birthday of %s""" % names
send_mail(all_mails, body, body)
def test_send_mail():
notify_body = """Tomorrow is birthday of """
recipients = ['MYBOT@gmail.com']
today = datetime.now()
format = "%d-%m-%Y"
print today
today_in_str = datetime.strftime(today, format)
def read_csv():
FILENAME = 'mails.csv'
reader = csv.reader(open(FILENAME, 'rt'), delimiter=',')
today = datetime.now()
one_day = timedelta(days=1)
tomorrow = today + one_day
all_mails = []
str_format = "%d/%m"
str_today = today.strftime(str_format)
str_tomorrow = tomorrow.strftime(str_format)
print 'Today is ', str_today
tomorrow_birth = []
for row in reader:
name = row[1].strip()
dob = row[2]
dmy = dob.split("/")
mail = row[3]
all_mails.append(mail)
#TODO fix dob with only 1 digit
birth_date = dmy[0] + "/" + dmy[1]
if str_today == birth_date:
print 'Happy birthday %s' % name
try:
send_happybirthday(mail)
except Exception, e:
print e
elif str_tomorrow == birth_date:
tomorrow_birth.append(name)
print "Tomorrow is %s's birthday" % name
# Remove empty string
all_mails = filter(None, all_mails)
print 'All mails: ', len(all_mails)
str_all_mails = ', '.join(all_mails)
if tomorrow_birth:
all_tomorrow = ', '.join(tomorrow_birth)
send_notification(str_all_mails, all_tomorrow)
def main():
read_csv()
if __name__ == "__main__":
main()
Can anyone explain this. Thanks!
I found solution from here
Send Email to multiple recipients from .txt file with Python smtplib
I passed a string contain all recipients separated by comma to msg['To'] and sendmail(). It's true for msg['To'] but with sendmail, I have to use a list.
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