在Golang中解组json:必填字段? [英] Unmarshaling json in Golang: required field?
本文介绍了在Golang中解组json:必填字段?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果在Golang中解组时未在json中找到字段,是否可能生成错误?我无法在文档中找到它。是否有任何标签指定该字段为必填项?
Is it possible to generate an error if a field was not found in json while unmarshaling in Golang? I could not find it in documentation. Is there any tag that specifies the field as required?
推荐答案
包将字段设置为required。您将不得不编写自己的 MarshalJSON()
方法,或者对丢失的字段进行检查。
There is no tag in the encoding/json
package that sets a field to "required". You will either have to write your own MarshalJSON()
method, or do a post check for missing fields.
要检查缺少的字段,您将不得不使用指针来区分missing / null和零值:
To check for missing fields, you will have to use pointers in order to distinguish between missing/null and zero values:
type JsonStruct struct {
String *string
Number *float64
}
完整的工作示例:
Full working example:
package main
import (
"fmt"
"encoding/json"
)
type JsonStruct struct {
String *string
Number *float64
}
var rawJson = []byte(`{
"string":"We do not provide a number"
}`)
func main() {
var s *JsonStruct
err := json.Unmarshal(rawJson, &s)
if err != nil {
panic(err)
}
if s.String == nil {
panic("String is missing or null!")
}
if s.Number == nil {
panic("Number is missing or null!")
}
fmt.Printf("String: %s Number: %f\n", *s.String, *s.Number)
}
这篇关于在Golang中解组json:必填字段?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文