请参阅常量或包级变量而不是函数级变量 [英] Refer to constant or package level variable instead of function level variable
问题描述
package main
importfmt
const name =Yosua
// var name name string =James
func main(){
name:=Jobs
fmt.Println(name)
}
$ c
$ b 如何引用常量而不是函数级变量?
解决方案你不能。虽然局部变量 name
在范围内,但名称 name
表示局部变量。并且没有限定符来指代顶级标识符。
块中声明的标识符可以在内部重新声明块。虽然内部声明的标识符在范围内,但它表示由内部声明声明的实体。
如果您需要同时访问顶级常量/变量和局部变量同时使用不同的名字。
如果由于某种原因你不能或不想,您可以先保存顶层常量或变量的值:
cname:= name
name:= 作业
fmt.Println(名称)
fmt.Println(cname)
<或者您可以提供其他方式来访问它,例如一个函数:
func getName()字符串{
返回名称
}
name:=Jobs
fmt.Println(name)
fmt.Println(getName())
在这两种情况下输出(在去游乐场试试):
工作
Yosua
package main
import "fmt"
const name = "Yosua"
// or var name string = "James"
func main() {
name := "Jobs"
fmt.Println(name)
}
How to refer to the constant and not the the function level variable?
解决方案 You can't. While the local variable name
is in scope, the name name
denotes the local variable. And there is no "qualifier" to refer to top-level identifiers.
An identifier declared in a block may be redeclared in an inner block. While the identifier of the inner declaration is in scope, it denotes the entity declared by the inner declaration.
If you need to access both the top-level constant/variable and the local variable at the same time, use different names.
If for some reason you can't or don't want to, you may save the value of the top-level constant or variable first:
cname := name
name := "Jobs"
fmt.Println(name)
fmt.Println(cname)
Or you may provide other means to access it, e.g. a function:
func getName() string {
return name
}
name := "Jobs"
fmt.Println(name)
fmt.Println(getName())
Output in both cases (try them on the Go Playground):
Jobs
Yosua
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