int16转换为字节数组 [英] int16 to byte array

问题描述

我试图将一个int16转换为一个字节数组，但我似乎无法使它工作。

这是我现在所拥有的：

  int16 i：= 41 
a：= [] byte（string（i））// this line is wrong 
  

另外如果有人想知道数组需要长度为2。 >解决方案

如果你想得到一个int16的字节，试试这样：

  var i int16 = 41 
 var h，l uint8 = uint8（i>> 8），uint8（i& 0xff）
  

Go尝试使编写依赖于平台属性（例如字节顺序）的程序变得困难。因此，禁止导致这种依赖的类型双引号（例如用int16覆盖字节数组）。

如果您真的想在脚下自拍，请试用不安全的软件包。

I'm trying to convert a int16 to a byte array but i cant seem to get it to work.
Here is what i've got right now:

int16 i := 41
a := []byte(string(i))//this line is wrong

Also if someone wonder the array needs to be a length of 2.

解决方案

If you want to get the bytes of an int16, try something like this:

var i int16 = 41
var h, l uint8 = uint8(i>>8), uint8(i&0xff)

Go tries to make it difficult to write programs that depend on attributes of your platform such as byte order. Thence, type punning that leads to such dependencies (such as overlaying a byte-array with an int16) is forbidden.

In case you really want to shoot yourself in the foot, try the package unsafe.

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