Golang数字的字母表示 [英] Golang Alphabetic representation of a number
问题描述
有没有简单的方法将数字转换为字母？
例如，
3 => C和 23 => W？
所有可以在去游乐场尝试。
Number - > rune
只需将数字添加到常量'A ' - 1 所以添加 1 就可以得到'A'，并添加 2 您可以得到'B'等：
func toChar（i int）rune {
return rune（'A' - 1 + i）
}
测试它：
for _，i：= range [] int {1,2,23,26} {
fmt.Printf（％d％q \ n，i，toChar（i））
}
1'A'>
>
2'B'
23'W'
26'Z'
数字 - > 字符串
或者如果您想将它作为字符串 $ b $ pre $ func toCharStr（i int）string {
return string（'A' - 1 + i ）
}
输出：
1A
2B
23W
26Z
最后一个（将数字转换为 string ）记录在规范：与字符串类型的转换：
将带符号或无符号整数值转换为字符串类型将生成一个包含整数的UTF-8表示形式的字符串。
Number - > string （cached）
如果您需要很多次这样做，在a中存储字符串是有利的例如，n数组，然后返回字符串：
var arr =字符串{A，B，C，D，E，F，G，H，I，J， K，L，M，
，N，O，P，Q，R，S，T，U，V ，W，X，Y，Z}
func toCharStrArr（i int）string {
return arr [i-1]
}
注意：切片（而不是数组）也可以。
注意＃2：如果你添加一个虚拟的第一个字符，你可以改进它，所以你不必从<$ c中减去 1
$ b
var arr = [...] string {。， A，B，C，D，E，F，G，H，I，J，K，L，M ，$，O，P，Q，R，S，T，U，V，W，X Y，Z}
func toCharStrArr（i int）string {return arr [i]}
Number - > string （切分字符串常量）
另一个有趣的解决方案是：
const abc =ABCDEFGHIJKLMNOPQRSTUVWXYZ
func toCharStrConst（i int）string {
return abc [i-1： i]
}
切分字符串是高效的：新的字符串将共享后备数组（可以这样做，因为 string s是不可变的） 。
Is there an easy way to convert a number to a letter?
For example,
3 => "C" and 23 => "W"?
For simplicity range check is omitted from below solutions.
They all can be tried on the Go Playground.
Number -> rune
Simply add the number to the const 'A' - 1 so adding 1 to this you get 'A', adding 2 you get 'B' etc.:
func toChar(i int) rune {
return rune('A' - 1 + i)
}
Testing it:
for _, i := range []int{1, 2, 23, 26} {
fmt.Printf("%d %q\n", i, toChar(i))
}
Output:
1 'A'
2 'B'
23 'W'
26 'Z'
Number -> string
Or if you want it as a string:
func toCharStr(i int) string {
return string('A' - 1 + i)
}
Output:
1 "A"
2 "B"
23 "W"
26 "Z"
This last one (converting a number to string) is documented in the Spec: Conversions to and from a string type:
Converting a signed or unsigned integer value to a string type yields a string containing the UTF-8 representation of the integer.
Number -> string (cached)
If you need to do this a lot of times, it is profitable to store the strings in an array for example, and just return the string from that:
var arr = [...]string{"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M",
"N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"}
func toCharStrArr(i int) string {
return arr[i-1]
}
Note: a slice (instead of the array) would also be fine.
Note #2: you may improve this if you add a dummy first character so you don't have to subtract 1 from i:
var arr = [...]string{".", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M",
"N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"}
func toCharStrArr(i int) string { return arr[i] }
Number -> string (slicing a string constant)
Also another interesting solution:
const abc = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
func toCharStrConst(i int) string {
return abc[i-1 : i]
}
Slicing a string is efficient: the new string will share the backing array (it can be done because strings are immutable).
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