Golang记录http响应（除了请求） [英] Golang logging http responses (in addition to requests)

问题描述

我使用Go和Gorilla web工具包的mux和handler程序包来构建一个复杂的应用程序，其中一部分需要http服务器。 Gorilla的多路复用器和处理程序包非常好用，我能够成功地启动和运行http服务器，并且记录请求非常简单。

但是，我无法确定如何记录回复。理想情况下，我想要一个类似于Gorilla的LoggingHandler的机制，它可以轻松包装日志机制。

是否有Golang包可以轻松打包/记录响应？有没有办法使用Go或Gorilla的功能，我没有考虑过？

我尝试了一些建议，并着手于使用简约包装的相当简单的解决方案。以下是适合我的解决方案（可随意提供评论，或更好的解决方案）：

  import（
fmt
log
net / http
net / http / httptest
net / http / httputil
github .com / gorilla / mux
）
：
 
 func logHandler（fn http.HandlerFunc）http.HandlerFunc {
 return func（w http.ResponseWriter，r * http.Request）{
x，err：= httputil.DumpRequest（r，true）
 if err！= nil {
 http.Error（w，fmt.Sprint（err），http .StatusInternalServerError）
 return 
 
 log.Println（fmt.Sprintf（％q，x））
 rec：= httptest.NewRecorder（）
 fn （rec，r）
 log.Println（fmt.Sprintf（％q，rec.Body））
} 
} 
 
 func MessageHandler（w http .ResponseWriter，r * http.Request）{
 fmt.Fprintln（w，A message was received）
} 
  

和fol低代码将使用上述处理程序：

 ：
 router：= mux.NewRouter（）
 router .HandleFunc（/，logHandler（MessageHandler））
：
  

代码将沿着以下方向行事：

 ：
 2016/07/20 14:44:29GET ... HTTP / 1.1 \r\\\
Host：localhost：8088\r\\\
Acept：* / * \r\\\
User-Agent：curl / 7.43.0\r\\\
\r\\ \\ n
 2016/07/20 14:44:29 ... [回复正文] 
：
  

I am using Go and the Gorilla web toolkit's mux and handler packages to build a complex application, part of which requires a http server. Gorilla's mux and handler packages work wonderfully and I am able to successfully get the http server up and running and it has been quite simple to log requests.

However, I am unable to determine how I may log responses. Ideally, I would like a mechanism, similar to Gorilla's LoggingHandler, that "wraps" the logging mechanism easily.

Is there a Golang package that does easily wraps / logs responses? Is there a way to use Go or Gorilla's capabilities in this fashion that I have not considered?

解决方案

Thanks for the great suggestions. I tried a few of the suggestions and landed on a rather simple solution that uses a minimalist wrapper. Here is the solution that worked for me (feel free to offer comments, or better yet, other solutions):

import (
    "fmt"
    "log"
    "net/http"
    "net/http/httptest"
    "net/http/httputil"
    "github.com/gorilla/mux"
)
:

func logHandler(fn http.HandlerFunc) http.HandlerFunc {
    return func(w http.ResponseWriter, r *http.Request) {
        x, err := httputil.DumpRequest(r, true)
        if err != nil {
            http.Error(w, fmt.Sprint(err), http.StatusInternalServerError)
            return
        }
        log.Println(fmt.Sprintf("%q", x))
        rec := httptest.NewRecorder()
        fn(rec, r)
        log.Println(fmt.Sprintf("%q", rec.Body))            
    }
}

func MessageHandler(w http.ResponseWriter, r *http.Request) {
    fmt.Fprintln(w, "A message was received")
}

And the following code will use the aforementioned handler:

:
router := mux.NewRouter()
router.HandleFunc("/", logHandler(MessageHandler))
:

Output from the above code will be something along the lines of:

:
2016/07/20 14:44:29 "GET ... HTTP/1.1\r\nHost: localhost:8088\r\nAccept: */*\r\nUser-Agent: curl/7.43.0\r\n\r\n"
2016/07/20 14:44:29 ...[response body]
:

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