如何递归地将字符串连接到golang中的字符串类型数组 [英] How to recursively join a string to an array of type string in golang
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问题描述
像这样:
加入,[one,two,three]
应该看起来像这样的一,二,三
解决方案已经有加入函数
strings
模块。但它不是递归的,如果你需要递归,你可以像这样做:
包主
导入fmt
func join_helper(splitter string,arrOfStrings [] string,res string)string {
if len(arrOfStrings)== 0 {
return res
}
if len(arrOfStrings)== 1 {
return join_helper(splitter,arrOfStrings [1:],res + arrOfStrings [0])
}
return join_helper(splitter,arrOfStrings [1:],res + arrOfStrings [0] + splitter)
}
$ b func join(splitter string,arrOfStrings [] string)string {
return join_helper(splitter,arrOfStrings,)
}
func main(){
fmt.Println(join(,,[] string { a,b,c,d}))
}
I am struggling with this for quite some time. I basically want to create a function that recursively join a string to an array.
Like this :
join ", " ["one","two","three"] should look like this "one, two, three"
解决方案There is already Join function in
strings
module. But it's not recursive, if you need recursive you can make it like this:package main import "fmt" func join_helper(splitter string, arrOfStrings []string, res string) string { if len(arrOfStrings) == 0 { return res } if len(arrOfStrings) == 1 { return join_helper(splitter, arrOfStrings[1:], res + arrOfStrings[0]) } return join_helper(splitter, arrOfStrings[1:], res + arrOfStrings[0] + splitter) } func join(splitter string, arrOfStrings []string) string { return join_helper(splitter, arrOfStrings, "") } func main(){ fmt.Println(join(",", []string{"a", "b", "c", "d"})) }
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