你如何上传文件作为流? [英] How can you upload files as a stream in go?

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本文介绍了你如何上传文件作为流?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

有很多关于使用 http.Request 发布文件的教程,但几乎总是像这样开始:

There are a number of tutorials about posting files using http.Request in go, but almost invariably they start like this:

file, err := os.Open(path)
if err != nil {
    return nil, err
}
fileContents, err := ioutil.ReadAll(file)

也就是说,整个文件存储到内存中,然后将其转换为 Buffer 并将其传递到请求中,如下所示:

Which is to say, you read the entire file into memory, and then convert it into a Buffer and pass that into a request, something like this:

func send(client *http.Client, file *os.File, endpoint string) {
    body := &bytes.Buffer{}
    io.Copy(body, file)
    req, _ := http.NewRequest("POST", endpoint, body)
    resp, _ := client.Do(req)
}

如果您想发布大量文件并避免将其读入内存, 。你会怎么做?

If you wanted to post a massive file and avoid reading it into memory, but instead steam the file up in chunks... how would you do that?

推荐答案

如果你需要设置 Content-Length ,可以手动完成。以下片段是将文件和额外参数作为流上传的示例(基于 Golang的无缓冲区多部分POST)

If you need to set Content-Length, it can be done manually. The following snippet is an example of uploading file and extra parameters as a stream (the code based on Buffer-less Multipart POST in Golang)

//NOTE: for simplicity, error check is omitted
func uploadLargeFile(uri, filePath string, chunkSize int, params map[string]string) {
    //open file and retrieve info
    file, _ := os.Open(filePath)
    fi, _ := file.Stat()
    defer file.Close()    

    //buffer for storing multipart data
    byteBuf := &bytes.Buffer{}

    //part: parameters
    mpWriter := multipart.NewWriter(byteBuf)
    for key, value := range params {
        _ = mpWriter.WriteField(key, value)
    }

    //part: file
    mpWriter.CreateFormFile("file", fi.Name())
    contentType := mpWriter.FormDataContentType()

    nmulti := byteBuf.Len()
    multi := make([]byte, nmulti)
    _, _ = byteBuf.Read(multi)    

    //part: latest boundary
    //when multipart closed, latest boundary is added
    mpWriter.Close()
    nboundary := byteBuf.Len()
    lastBoundary := make([]byte, nboundary)
    _, _ = byteBuf.Read(lastBoundary)

    //calculate content length
    totalSize := int64(nmulti) + fi.Size() + int64(nboundary)
    log.Printf("Content length = %v byte(s)\n", totalSize)

    //use pipe to pass request
    rd, wr := io.Pipe()
    defer rd.Close()

    go func() {
        defer wr.Close()

        //write multipart
        _, _ = wr.Write(multi)

        //write file
        buf := make([]byte, chunkSize)
        for {
            n, err := file.Read(buf)
            if err != nil {
                break
            }
            _, _ = wr.Write(buf[:n])
        }        
        //write boundary
        _, _ = wr.Write(lastBoundary)        
    }()

    //construct request with rd
    req, _ := http.NewRequest("POST", uri, rd)
    req.Header.Set("Content-Type", contentType)
    req.ContentLength = totalSize

    //process request
    client := &http.Client{}
    resp, err := client.Do(req)
    if err != nil {
        log.Fatal(err)
    } else {
        log.Println(resp.StatusCode)
        log.Println(resp.Header)

        body := &bytes.Buffer{}
        _, _ = body.ReadFrom(resp.Body)
        resp.Body.Close()
        log.Println(body)
    }
}

这篇关于你如何上传文件作为流?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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