golang从sdin扫描一行数字 [英] golang scan a line of numbers from sdin
问题描述
我试图从stdin读取输入,例如
3 2 1< ENTER>
并将其保存在整数列表中。目前我的代码如下所示:
$ $ p $ $ $ $ $ $ $
for {
_,err:= fmt.Scan(& i)
if err!= nil {
if err == io.EOF {break}
log.Fatal(err)
}
nums = append(nums,i)
}
程序从不离开for循环。我找不到在文档中检查换行符的简单方法。我怎么会这样做?
编辑:
因为我知道几乎肯定会有四个数字,我尝试了以下方法:
var i0,i1,i2,i3 int
fmt.Scanf(%d% d%d%d \ n,& i0,& i1,& i2,& i3)
但这只扫描了第一个数字,然后退出程序。我不确定是否因为我使用的z-shell。
编辑:
为了澄清,程序将暂停并要求用户输入由空格分隔的n个数字的列表并以换行符结束。这些数字应该存储在一个数组中。
好的,我决定带出大型bufio锤子并像这样解决:
in:= bufio.NewReader(os.Stdin)
line,err:= in.ReadString(' \ n')
if err!= nil {
log.Fatal(err)
}
strs:= strings.Split(line [0:len(line) - 1],)
nums:= make([] int,len(strs))
for i,str:=范围strs {
如果nums [i],err = strconv .Atoi(STR); err!= nil {
log.Fatal(err)
}
}
它看起来好像很多代码,但它有效。
I'm trying to read input from stdin like
3 2 1<ENTER>
and save it in a list of ints. At the moment my code looks like this:
nums = make([]int, 0)
var i int
for {
_, err := fmt.Scan(&i)
if err != nil {
if err==io.EOF { break }
log.Fatal(err)
}
nums = append(nums, i)
}
at the moment the program never leaves the for-loop. I can't find an easy way to check for a newline character in the documentation. how would i do this?
Edit:
Since I know that there will almost certainly be four numbers, I tried the following:
var i0,i1,i2,i3 int
fmt.Scanf("%d %d %d %d\n", &i0, &i1, &i2, &i3)
but this only scanned the first number and then exited the program. I'm not sure if that's because of the z-shell I'm using.
Edit:
To clarify, the program will pause and ask for the user to input a list of n numbers separated by spaces and terminated with a newline. these numbers should be stored in an array.
Ok, I decided to bring out the large bufio hammer and solve it like this:
in := bufio.NewReader(os.Stdin)
line, err := in.ReadString('\n')
if err != nil {
log.Fatal(err)
}
strs := strings.Split(line[0:len(line)-1], " ")
nums := make([]int, len(strs))
for i, str := range strs {
if nums[i], err = strconv.Atoi(str); err != nil {
log.Fatal(err)
}
}
It does seem like an awful lot of code, but it works.
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