用整数范围生成数组 [英] Generate array with with range of integers

问题描述

我有两个值：

I have two values:

[3：6]

[3:6]

我试图在Golang中玩弄一些东西，但我无法找到一个好方法根据这些值创建一个数组。

I was trying to play something around in Golang but I can't manage to find a good method to create an array according to those values.

这是我想达到的目的：

This what I would like to achieve:

[3,4,5,6]

推荐答案

您可以使用 / code>构造使其更紧凑，甚至更快：



You can make use of the for ... range construct to make it more compact and maybe even faster:

lo, hi := 3, 6
s := make([]int, hi-lo+1)
for i := range s {
    s[i] = i + lo
}

作为好奇心，循环可以在没有循环变量的情况下实现，但会更慢，代码更长。通过递减 hi ：

As a matter of curiosity, the loop can be implemented without a loop variable, but it will be slower, and the code longer. By decrementing hi:

for ; hi >= lo; hi-- {
    s[hi-len(s)+1] = hi
}

或递增 lo ：

Or incrementing lo:

for ; lo <= hi; lo++ {
    s[len(s)-1-hi+lo] = lo
}

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