如何控制机器人的活动栈/清除活性堆栈 [英] How to control activity stack/clear activity stack in Android

问题描述

我有去如下的应用程序（主页是发射活动）：

I have an application that goes as follows (Home being the launch activity):

D
C
B
A
Home

我的流转如下：

My flow goes as follows:

用户启动的活动 A 从首页，流向 B 和 C 。当用户离开活动 C ，我想 A ， B 和 C 被破坏。也就是说，如果用户presses 返回的活动 D ，它可以追溯到首页。

The user starts activity A from Home, which flows to B and C. When the user leaves activity C, I want A, B, and C to be destroyed. That is, if the user presses BACK in activity D, it goes back to Home.

用户必须能够控制程序正常流过活动 A ， B 和<$ C $ ç> C 。所以，如果他们preSS的活动 C 返回按钮，它可以追溯到活动 B 。

The user must be able to control program flow normally through activityA, B, and C. So if they press the back button in activityC, it goes back to activity B.

我已经看了意向标志，如 CLEAR_TOP 和 NEW_TASK ，但他们都不做我希望他们。

I've looked at Intent flags such as CLEAR_TOP and NEW_TASK, but none of them seem to do what I want them to.

我想AP preciate任何帮助！

I'd appreciate any help!

推荐答案

也许你正在寻找的 FLAG_ACTIVITY_TASK_ON_HOME ？它需要API级别11，但：（

Perhaps you are looking for FLAG_ACTIVITY_TASK_ON_HOME? It requires API level 11 though :(

有关API级＆LT; 11，这是可以做到：

for API level <11, this can be done:

开始活动B和C时，使用startActivityForResult（）。当开始活动研发，做到这一点：

when starting activity B and C, use startActivityForResult(). When starting activity D, do this:

startActivity(D);
setResult(KILL_YOURSELF); //KILL_YOURSELF is some arbitrary int that you use to identify that the other activities should exit
finish(); //finish the activity

这会杀了活动℃，然后在活动A和B，覆盖onActivityResult是这样的：

This will kill activity C. Then in activity A and B, override onActivityResult like this:

@Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

        if(resultCode == KILL_YOURSELF) {
            setResult(KILL_YOURSELF);
            finish();
        }
    }

因此​​b活动将结束，这反过来会触发onActivityResult在A，所以它也将完成。

Thus activity B will finish, which in turn will trigger onActivityResult in A, so it will also finish.

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