谷歌语音到C＃中的文本API [英] Google speech to text API in C#
本文介绍了谷歌语音到C＃中的文本API的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
当flac文件通过使用windows录音机录制手册并使用软件转换器进行转换时，我的程序从google获得正确的响应。
但是，当我使用我的程序记录的文件时，我从google获得了{结果：[]}
。我该怎么办？
这里是我的代码：
发件人：
private static void CopyStream（FileStream fileStream，Stream requestStream）
{
var buffer = new byte [32768];
int读取; （（read = fileStream.Read（buffer，0，buffer.Length））> 0）
{
requestStream.Write（buffer，0，read）;
private静态无效ConfigureRequest（HttpWebRequest请求）
{
request.KeepAlive = true;
request.SendChunked = true;
request.ContentType =audio / x-flac; rate = 44100;
request.UserAgent =
Mozilla / 5.0（Windows NT 6.2; WOW64）AppleWebKit / 535.2（KHTML，如Gecko）Chrome / 15.0.874.121 Safari / 535.2;
request.Headers.Set（HttpRequestHeader.AcceptEncoding，gzip，deflate，sdch）;
request.Headers.Set（HttpRequestHeader.AcceptLanguage，en-GB，en-US; q = 0.8，en; q = 0.6）;
request.Headers.Set（HttpRequestHeader.AcceptCharset，ISO-8859-1，utf-8; q = 0.7，*; q = 0.3）;
request.Method =POST;
using（var fileStream = new FileStream（@C：\ Users \Ahmad Mustofa \Documents\Visual Studio 2010\Projects\FP\FP\\\\\\\\ Debug \voice.flac，FileMode.Open））
{
const string requestUrl =https://www.google.com/speech-api/v2/recognize?output=json&lang = AR-SA&安培;键= AIzaSyBJ6VJ326Rpb23msih2wGhXENEwU1TF1PA&安培;客户=铬&安培;的maxResults = 1&安培; pfilter = 2\" ;
var request =（HttpWebRequest）WebRequest.Create（requestUrl）;
ConfigureRequest（request）;
var requestStream = request.GetRequestStream（）;
CopyStream（fileStream，requestStream）;
using（var response = request.GetResponse（））
{
using（var responseStream = response.GetResponseStream（））
{
using（ var zippedStream = new GZipStream（responseStream，CompressionMode.Decompress））
{
using（var sr = new StreamReader（zippedStream））
{
var res = sr.ReadToEnd（） ;
state.Text = res;
}
}
}
}
}
wav录音机：
private void sourceStream_DataAvailable（object sender，NAudio.Wave.WaveInEventArgs e）
{
if（waveWriter == null）return;
waveWriter.WriteData（e.Buffer，0，e.BytesRecorded）;
waveWriter.Flush（）;
}
fileName =C：\\ Users \\Ahmad Mustofa \\Documents\\Visual Studio 2010\\Projects\\\\\\\\ \\FP\\bin\\debug\\voice.wav;
int deviceNumber = hardware.SelectedItems [0] .Index;
尝试
{
sourceStream = new NAudio.Wave.WaveIn（）;
sourceStream.DeviceNumber = deviceNumber;
sourceStream.WaveFormat = new NAudio.Wave.WaveFormat（44100，NAudio.Wave.WaveIn.GetCapabilities（deviceNumber）.Channels）;
sourceStream.DataAvailable + = new EventHandler< NAudio.Wave.WaveInEventArgs>（sourceStream_DataAvailable）;
waveWriter = new NAudio.Wave.WaveFileWriter（fileName，sourceStream.WaveFormat）;
sourceStream.StartRecording（）;
}
catch（Exception ex）
{
state.Text =disini+ ex.Message;
}
flac转换器：
string inputFile = Path.Combine（wav，input）;
string outputFile = Path.Combine（flac，Path.ChangeExtension（input，.flac））;
if（！File.Exists（inputFile））
抛出新的ApplicationException（Input file+ inputFile +could not be found！）;
WavReader wav = new WavReader（inputFile）;
使用（var flacStream = File.Create（outputFile））
{
FlacWriter flac = new FlacWriter（flacStream，wav.BitDepth，wav.Channels，wav.SampleRate）;
// 1秒钟音频数据的缓冲区
byte [] buffer = new byte [wav.Bitrate / 8];
int bytesRead;
do
{
bytesRead = wav.InputStream.Read（buffer，0，buffer.Length）;
flac.Convert（buffer，0，bytesRead）;
} while（bytesRead> 0）;
flac.Dispose（）;
flac = null;
}
解决方案
问题，但提出了一个整洁的解决方案。我使用Fiddler（ http://www.telerik.com/fiddler/ ）了解Chrome进行语音识别，然后创建一些代码来模拟发送请求的chrome。此方法使用不同的URI，并且还有一个称为对的16个字符的值，对于每个请求都是不同的。我使用一个简单的随机值生成器函数为请求创建一个函数，并将输出值更改为'json'。
注意：结果有时可能是空的，就像上面的情况一样，但是响应中还有另一个json对象，它包含了替代方法。
private void GoogleSpeechToText（）
{
string uri =https://www.google.com/speech-api/full-duplex/v1/up?output=json&key=AIzaSyBOti4mM-6x9WDnZIjIeyEU21OpBXqWBgw&pair =+ GenerateUnique（16）+& lang = zh-CN& pFilter = 2& maxAlternatives = 10& client = chromium;
HttpWebRequest请求=（HttpWebRequest）WebRequest.Create（uri）;
request.Timeout = 10000;
request.Method =POST;
request.Host =www.google.com;
request.KeepAlive = true;
request.SendChunked = true;
request.ContentType =audio / x-flac; rate = 16000;
request.Headers.Set（HttpRequestHeader.AcceptLanguage，en-GB，en-US; q = 0.8，en; q = 0.6）;
request.UserAgent =Mozilla / 5.0（Windows NT 6.3; WOW64）AppleWebKit / 537.36（KHTML，如Gecko）Chrome / 36.0.1985.143 Safari / 537.36;
string path = @C：\TestFolder\test_audio.flac;
FileInfo fInfo = new FileInfo（path）;
var numBytes = fInfo.Length;
byte [] data;
using（FileStream fStream = new FileStream（path，FileMode.Open，FileAccess.Read））
{
data = new Byte [numBytes];
fStream.Read（data，0，（int）numBytes）;
fStream.Close（）;
using（Stream reqStream = request.GetRequestStream（））
reqStream.Write（data，0，data.Length）;
尝试
{
WebResponse response = request.GetResponse（）;
Stream respStream = response.GetResponseStream（）;
if（response.ContentType ==application / json; charset = utf-8）
{
using（var sr = new StreamReader（respStream））
{
var res = sr.ReadToEnd（）;
textBox1.Text = res;
}
}
}
catch（Exception ex）{MessageBox.Show（ex.Message，Error，MessageBoxButtons.OK）; }
}
private string GenerateUnique（int length）
{
string [] LETTERS = new string [] {A，B，C D，E，F，G，H，I，J，K，L，M，N，O， P，Q，R，S，T，U，V，W，X，Y，Z
string [] DIGITS =新字符串[] {0，1，2，3，4，5，6，7，8 9};
string buffer =;
Random random = new Random（）;
for（int i = 0; i
int rnd = random.Next（2）;
if（rnd == 1）
buffer + = LETTERS [random.Next（LETTERS.Length）];
else
buffer + = DIGITS [random.Next（DIGITS.Length）];
}
返回缓冲区;
}
My program get a correct respon from google when the flac file recorded manual by using windows's sound recorder and convert it using a software converter.
But when I use the file that recorded by my program, I got "{"result":[]}
" from google. What should I do?
here is my code :
the sender :
private static void CopyStream(FileStream fileStream, Stream requestStream)
{
var buffer = new byte[32768];
int read;
while ((read = fileStream.Read(buffer, 0, buffer.Length)) > 0)
{
requestStream.Write(buffer, 0, read);
}
}
private static void ConfigureRequest(HttpWebRequest request)
{
request.KeepAlive = true;
request.SendChunked = true;
request.ContentType = "audio/x-flac; rate=44100";
request.UserAgent =
"Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/535.2 (KHTML, like Gecko) Chrome/15.0.874.121 Safari/535.2";
request.Headers.Set(HttpRequestHeader.AcceptEncoding, "gzip,deflate,sdch");
request.Headers.Set(HttpRequestHeader.AcceptLanguage, "en-GB,en-US;q=0.8,en;q=0.6");
request.Headers.Set(HttpRequestHeader.AcceptCharset, "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
request.Method = "POST";
}
using (var fileStream = new FileStream(@"C:\Users\Ahmad Mustofa\Documents\Visual Studio 2010\Projects\FP\FP\bin\Debug\voice.flac", FileMode.Open))
{
const string requestUrl = "https://www.google.com/speech-api/v2/recognize?output=json&lang=ar-sa&key=AIzaSyBJ6VJ326Rpb23msih2wGhXENEwU1TF1PA&client=chromium&maxresults=1&pfilter=2";
var request = (HttpWebRequest)WebRequest.Create(requestUrl);
ConfigureRequest(request);
var requestStream = request.GetRequestStream();
CopyStream(fileStream, requestStream);
using (var response = request.GetResponse())
{
using (var responseStream = response.GetResponseStream())
{
using (var zippedStream = new GZipStream(responseStream, CompressionMode.Decompress))
{
using (var sr = new StreamReader(zippedStream))
{
var res = sr.ReadToEnd();
state.Text = res;
}
}
}
}
}
the wav recorder:
private void sourceStream_DataAvailable(object sender, NAudio.Wave.WaveInEventArgs e)
{
if (waveWriter == null) return;
waveWriter.WriteData(e.Buffer, 0, e.BytesRecorded);
waveWriter.Flush();
}
fileName = "C:\\Users\\Ahmad Mustofa\\Documents\\Visual Studio 2010\\Projects\\FP\\FP\\bin\\debug\\voice.wav";
int deviceNumber = hardware.SelectedItems[0].Index;
try
{
sourceStream = new NAudio.Wave.WaveIn();
sourceStream.DeviceNumber = deviceNumber;
sourceStream.WaveFormat = new NAudio.Wave.WaveFormat(44100, NAudio.Wave.WaveIn.GetCapabilities(deviceNumber).Channels);
sourceStream.DataAvailable += new EventHandler<NAudio.Wave.WaveInEventArgs>(sourceStream_DataAvailable);
waveWriter = new NAudio.Wave.WaveFileWriter(fileName, sourceStream.WaveFormat);
sourceStream.StartRecording();
}
catch (Exception ex)
{
state.Text = "disini" + ex.Message;
}
flac converter:
string inputFile = Path.Combine("wav ", input);
string outputFile = Path.Combine("flac", Path.ChangeExtension(input, ".flac"));
if (!File.Exists(inputFile))
throw new ApplicationException("Input file " + inputFile + " cannot be found!");
WavReader wav = new WavReader(inputFile);
using (var flacStream = File.Create(outputFile))
{
FlacWriter flac = new FlacWriter(flacStream, wav.BitDepth, wav.Channels, wav.SampleRate);
// Buffer for 1 second's worth of audio data
byte[] buffer = new byte[wav.Bitrate / 8];
int bytesRead;
do
{
bytesRead = wav.InputStream.Read(buffer, 0, buffer.Length);
flac.Convert(buffer, 0, bytesRead);
} while (bytesRead > 0);
flac.Dispose();
flac = null;
}
解决方案
I was also having the same issue but came up with a neat solution. I used Fiddler (http://www.telerik.com/fiddler/) to figure out how Chrome does the speech recognition and then created some code to emulate chrome sending the request. This approach uses a different URI and there is also a 16-character value called pair which is different for each request. I use a simple random value generator function to create one for the request and I also changed the output value to 'json'.
Note: The result can sometimes be empty as in your case above but there's also another json object in the response that contains the alternatives.
private void GoogleSpeechToText()
{
string uri = "https://www.google.com/speech-api/full-duplex/v1/up?output=json&key=AIzaSyBOti4mM-6x9WDnZIjIeyEU21OpBXqWBgw&pair=" + GenerateUnique(16) + "&lang=en-US&pFilter=2&maxAlternatives=10&client=chromium";
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
request.Timeout = 10000;
request.Method = "POST";
request.Host = "www.google.com";
request.KeepAlive = true;
request.SendChunked = true;
request.ContentType = "audio/x-flac; rate=16000";
request.Headers.Set(HttpRequestHeader.AcceptLanguage, "en-GB,en-US;q=0.8,en;q=0.6");
request.UserAgent = "Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/36.0.1985.143 Safari/537.36";
string path = @"C:\TestFolder\test_audio.flac";
FileInfo fInfo = new FileInfo(path);
var numBytes = fInfo.Length;
byte[] data;
using (FileStream fStream = new FileStream(path, FileMode.Open, FileAccess.Read))
{
data = new Byte[numBytes];
fStream.Read(data, 0, (int) numBytes);
fStream.Close();
}
using (Stream reqStream = request.GetRequestStream())
reqStream.Write(data, 0, data.Length);
try
{
WebResponse response = request.GetResponse();
Stream respStream = response.GetResponseStream();
if(response.ContentType == "application/json; charset=utf-8")
{
using (var sr = new StreamReader(respStream))
{
var res = sr.ReadToEnd();
textBox1.Text = res;
}
}
}
catch (Exception ex) { MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK); }
}
private string GenerateUnique(int length)
{
string[] LETTERS = new string[] { "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z" };
string[] DIGITS = new string[] { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
string buffer = "";
Random random = new Random();
for(int i = 0; i < length; i++)
{
int rnd = random.Next(2);
if (rnd == 1)
buffer += LETTERS[random.Next(LETTERS.Length)];
else
buffer += DIGITS[random.Next(DIGITS.Length)];
}
return buffer;
}
这篇关于谷歌语音到C＃中的文本API的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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