Google Admin SDK 403未授权访问此资源/ API [英] Google Admin SDK 403 Not Authorized to Access this Resource/API

问题描述

我在java web应用程序中使用以下代码尝试获取组的所有用户：

  GoogleCredential凭证= GoogleCredential.fromStream（Util.class.getResourceAsStream（ [credential_file]上传.json））createScoped（范围）。 
 
目录目录= new Directory.Builder（httpTransport，JSON_FACTORY，凭证）.build（）; 
 
 Directory.Members dirMem = directory.members（）; 
成员成员= dirMem.list（[group_email]）。execute（）; 
  

这会导致最后一行发生异常403（无权访问此资源/ API） dirMem.list ...）。

从文档（ https://developers.google.com/admin-sdk/directory/v1/guides/delegation ）和其他职位，我看到解决方案是使用 setServiceAccountUser（）来设置服务帐户用户。
但是，这意味着我必须使用p12文件而不是json文件（Google建议您在创建密钥时使用json文件）。

有没有办法在仍使用json文件的情况下解决此问题（它也涉及较少的代码）。

谢谢。 现在，我只是使用p12文件，如下所示：

https://developers.google。如果有人知道用json文件在这个问题中执行代码的方法，那么你可以使用json文件，随时评论/回答。

I use the following code in a java web application to try to get all users of a group:

GoogleCredential credential = GoogleCredential.fromStream(Util.class.getResourceAsStream("[credential_file].json")).createScoped(SCOPES);

Directory directory = new Directory.Builder(httpTransport, JSON_FACTORY, credential).build();

Directory.Members dirMem = directory.members();
Members members = dirMem.list("[group_email]").execute();

This results in an exception 403 (Not authorized to access this resource/API) on the last line (dirMem.list...).

From the documentation (https://developers.google.com/admin-sdk/directory/v1/guides/delegation) and other posts, I saw that the solution to this is to set a service account user with setServiceAccountUser(). However, this means that I have to use a p12 file instead of a json file (Google recommends using a json file when you create the key).

Is there any way to get around this issue while still using a json file (it also involves less code).

Thanks.

解决方案

For now, I am just using the p12 file as outlined here:

https://developers.google.com/admin-sdk/directory/v1/guides/delegation

If anyone knows of a way to execute the code in this question with a json file, feel free to comment/answer.

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