如何使用谷歌日历API从谷歌日历中获取所有事件 [英] how to get all events from google calendar using google calendar API

问题描述

参考这，我已经制作了一个获取信息的应用程序从谷歌日历事件使用谷歌API。我使用了上面URL中给出的相同代码。

现在有一个包含ME和XYZ两个日历名称的日历。如果我使用我的电子邮件ID，那么我只会收到Calendar =ME事件的详细信息。
我已经在下面的代码中使用了

  EventsResource.ListRequest request = service.Events.List（primary）; 
 request.TimeMin = dtStart; 
 request.TimeMax = dtEnd; 
 request.ShowDeleted = false; 
 request.SingleEvents = true; 
 request.OrderBy = EventsResource.ListRequest.OrderByEnum.StartTime; 
 Events events = request.Execute（）; 
  

如何获取所有事件详情？

解决方案

nofollow>活动：列表

返回指定日历上的活动。

HTTP请求

获取 https：/ /www.googleapis.com/calendar/v3/calendars/calendarId/events

您可以从文档中看到Events.list返回A日历的事件。如果您有多个日历，那么您还需要为该日历请求事件。

提示：您可能需要查看

CalendarList：list 返回用户日历列表中的条目。

这将返回用户有权访问的日历列表，然后您可以循环查看每个日历上的事件。

With reference of this I have made a application which gets information from google calendar event using google api. I have used the same code given in above URL.

Now there is one calendar with 2 calendar name like ME and XYZ. If I use my email Id then I only got the details of event with Calendar = "ME". I have used below code

            EventsResource.ListRequest request = service.Events.List("primary");
            request.TimeMin = dtStart;
            request.TimeMax = dtEnd;
            request.ShowDeleted = false;
            request.SingleEvents = true;
            request.OrderBy = EventsResource.ListRequest.OrderByEnum.StartTime;
            Events events = request.Execute();

How to get all the events details?

解决方案

Events: list

Returns events on the specified calendar.

HTTP request

GET https://www.googleapis.com/calendar/v3/calendars/calendarId/events

As you can see from the documentation Events.list returns the events for A calendar. If you have more then one calendar then you will need to request the events for that calendar as well.

Tip: You might want to look at

CalendarList: list Returns entries on the user's calendar list.

This will return a list of the calendars the user has access to then you can loop though the events on each one of them.

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