Google App脚本。检查Range1是否与Range2相交 [英] Google App Script. Check if Range1 intersects Range2
问题描述
我想在Google表格中使用与VBA的 intersect
类似的功能脚本。有没有一个好办法做到这一点?该函数必须返回:
RangeIntersect(R1,R2)= true
如果R1与R2有共同的单元格,如果R1没有与R2共用的单元格,
RangeIntersect(R1,R2)= false
预先感谢您。
速度测试
我希望函数尽可能快地工作。这是因为它将在 onEdit
函数内的循环中使用。如果您喜欢,请使用此脚本测试提供的功能:
function speedtest(){
var sheet;
sheet = SpreadsheetApp.getActiveSheet();
var rr1 = ['A1:C16','B2:B88','D1:D8','E1:E17','A18:B51','A13:A14','A17:C17'] ;
var r1,r2;
r1 = sheet.getRange(rr1 [0]);
var rr2 = [];
//为(var x = 0; x <30; x ++){
为(var i = 0; i r2 = sheet.getRange(rr1 [i]);
rr2.push(r2);
}
}
var C;
var start,end,time;
// timer start
for(var t = 0; t <10; t ++){
start = new Date()。getTime(); (var f = 0; f C = RangeIntersect(r1,rr2 [f]);
}
end = new Date()。getTime();
时间=结束 - 开始;
Logger.log('Execution time ='+ time);
$ b
函数RangeIntersect(R1,R2){
var LR1 = R1.getLastRow();
var Ro2 = R2.getRow();
if(LR1
var LR2 = R2.getLastRow();
var Ro1 = R1.getRow();
if(LR2
var LC1 = R1.getLastColumn();
var C2 = R2.getColumn();
if(LC1
var LC2 = R2.getLastColumn();
var C1 = R1.getColumn();
if(LC2
返回true;
$ p
$ b 这个脚本的工作速度快1.4倍,因为它每次返回当2个范围不相交时。
Good day everyone!
I'd like to have a function similiar to VBA's intersect
in Google Sheets Script. Is there a nifty way to do this? The function must return:
RangeIntersect(R1, R2) = true
if R1 has common cells with R2,
RangeIntersect(R1, R2) = false
if R1 has no common cell with R2
Thank you in advance.
Speed test
I want the function to work as fast as possible. That's because it would be used in loops inside onEdit
function. If you like, test provided function with this script:
function speedtest () {
var sheet;
sheet = SpreadsheetApp.getActiveSheet();
var rr1 = ['A1:C16', 'B2:B88', 'D1:D8', 'E1:E17', 'A18:B51', 'A13:A14', 'A17:C17'];
var r1, r2;
r1 = sheet.getRange(rr1[0]);
var rr2 = [];
// define some ranges
for (var x = 0; x < 30; x++) {
for (var i = 0; i < rr1.length; i++) {
r2 = sheet.getRange(rr1[i]);
rr2.push(r2);
}
}
var C;
var start, end, time;
// timer start
for (var t = 0; t < 10; t++) {
start = new Date().getTime();
for (var f = 0; f < rr2.length; f++) {
C = RangeIntersect(r1, rr2[f]);
}
end = new Date().getTime();
time = end - start;
Logger.log('Execution time = ' + time);
}
}
解决方案 I've made my own version of this script:
function RangeIntersect(R1, R2) {
var LR1 = R1.getLastRow();
var Ro2 = R2.getRow();
if (LR1 < Ro2) return false;
var LR2 = R2.getLastRow();
var Ro1 = R1.getRow();
if (LR2 < Ro1) return false;
var LC1 = R1.getLastColumn();
var C2 = R2.getColumn();
if (LC1 < C2) return false;
var LC2 = R2.getLastColumn();
var C1 = R1.getColumn();
if (LC2 < C1) return false;
return true;
}
This script works ~1.4 times faster because it returns each time when 2 ranges don't intersect.
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