当从js文件和chrome控制台运行时，regexp产生不同的匹配 [英] regexp resulting different matches when run from js file and chrome console

问题描述

  alert（您好@name，您的账户将会是在@date激活.match（/ @ {1} [\w _] + / g））; 
  

当我从文件运行代码时（使用浏览器打开文件）
我得到

  [你好，名字，你的，帐户，被激活，日期] 
  

但是，当我在 chrome开发者控制台

上运行它时get：

  [@ name，@ date] 
  

这里发生了什么？相同的代码d / t结果

更新：

@ funkwurm 试图在评论中提及使用Chrome开发人员工具检查页面时对代码进行的更改。

match（/ @ { 1} [\w _] + / g）改为 match（/ \ [\w _] + / g） p>

我使用 Grails 框架，所以我认为使用 slashy语法（/ /）导致了问题，因为Grails也使用该语法（由于冲突）。

因此将其更改为

  var pattern = new RegExp（@ {1} [\\w _] +，g）; 
 
 
 alert（你好@名，你的账号将在@date时激活.match（pattern））; 
  

但仍然没有效果，当我做 alert（pattern） code>我得到 / \ [\w _] + / g 仍然没有@。





更新 em>问题是，在使用Chrome开发人员工具检查它时缺少@字符（谢谢 @Lee Kowalkowski 了解详情）。

我试过 转义 ，但仍无法使用。

以下是我提出的解决方案：

  var pattern = new RegExp（String.fromCharCode（64）+{1} [\\w _] +，g）; // 64是@ 
  

的ascii值仍然渴望知道为什么@字符丢失了

This is weird, I have this statement in js code:

alert ( "Hello @name , your account will be activated at  @date".match(/@{1}[\w_]+/g) );

When I run the code from the file (opening the file using browser) I get

[hello,name,your,account,be,activated,date]

But when I run it on the chrome developer console
I get:

[@name,@date]

what is happening here? same code d/t result

update:

As @funkwurm tried to mention on the comment there is a change on the code when I inspect the page using chrome developer tool.
match(/@{1}[\w_]+/g) was changed to match(/\[\w_]+/g)

I am using Grails framework so I thought using the slashy syntax (/ /) was causing the problem because Grails also uses that syntax ( due to conflict).

so changed it to

var pattern = new RegExp("@{1}[\\w_]+","g");    


alert ( "Hello @name , your account will be activated at @date".match(pattern) );

but still no effect, and when I do alert(pattern) I get /\[\w_]+/g still without the @.

Thanks

解决方案

As I tried to mention on the update the problem was the @ character was missing when inspecting it using chrome developer tool ( Thanks @Lee Kowalkowski for the insight).

I tried escaping it but still did not work.

Here is the solution I came up with:

var pattern = new RegExp(String.fromCharCode(64)+"{1}[\\w_]+","g"); //64 is ascii value of @

Still eager to know why @ character was missing

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