如何从Python脚本上传Google云端存储中的字节图像 [英] How to upload a bytes image on Google Cloud Storage from a Python script

问题描述

我想从Python脚本上传Google云端存储中的图片。这是我的代码：

I want to upload an image on Google Cloud Storage from a python script. This is my code:

from oauth2client.service_account import ServiceAccountCredentials
from googleapiclient import discovery

scopes = ['https://www.googleapis.com/auth/devstorage.full_control']
credentials = ServiceAccountCredentials.from_json_keyfile_name('serviceAccount.json', scop
es)
service = discovery.build('storage','v1',credentials = credentials)

body = {'name':'my_image.jpg'}

req = service.objects().insert(
   bucket='my_bucket', body=body,
   media_body=googleapiclient.http.MediaIoBaseUpload(
      gcs_image, 'application/octet-stream'))

resp = req.execute()

if gcs_image =打开（'img.jpg'，'r'）代码正常工作，并将我的映像正确保存到云端存储上。我怎样才能直接上传一个字节图像？ （例如来自OpenCV / Numpy数组： gcs_image = cv2.imread（'img.jpg'））

if gcs_image = open('img.jpg', 'r') the code works and correctly save my image on Cloud Storage. How can I directly upload a bytes image? (for example from an OpenCV/Numpy array: gcs_image = cv2.imread('img.jpg'))

推荐答案

如果您想从文件上传图片。

If you want to upload your image from file.

import os
from google.cloud import storage

def upload_file_to_gcs(bucket_name, local_path, local_file_name, target_key):
    try:
        client = storage.Client()
        bucket = client.bucket(bucket_name)
        full_file_path = os.path.join(local_path, local_file_name)
        bucket.blob(target_key).upload_from_filename(full_file_path)
        return bucket.blob(target_key).public_url

    except Exception as e:
        print(e)

    return None

但是如果你想直接上传字节：

but if you want to upload bytes directly:

import os
from google.cloud import storage

def upload_data_to_gcs(bucket_name, data, target_key):
    try:
        client = storage.Client()
        bucket = client.bucket(bucket_name)
        bucket.blob(target_key).upload_from_string(data)
        return bucket.blob(target_key).public_url

    except Exception as e:
        print(e)

    return None

注意 target_key 是前缀和上传文件的名称。

note that target_key is prefix and the name of the uploaded file.

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