通过使用谷歌反向地理编码获得街道，城市和国家 [英] Getting street,city and country by reverse geocoding using google
问题描述
我试图从google json中获取$ street，$ city和$ country字符串。
适用于我的家庭住址：
http://maps.googleapis.com/maps/api/geocode/json?latlng=52.108662,6.307370&sensor=true
$ url =http://maps.googleapis.com/maps/api/geocode/json?latlng=\".$lat.\",\".$lng.\"&传感器=真;
$ data = @file_get_contents（$ url）;
$ jsondata = json_decode（$ data，true）;
if（is_array（$ jsondata）&& $ jsondata ['status'] ==OK）
{
$ city = $ jsondata ['results'] ['0 '] [' address_components '] [' 2 '] [' LONG_NAME'];
$ country = $ jsondata ['results'] ['0'] ['address_components'] ['5'] ['long_name'];
$ street = $ jsondata ['results'] ['0'] ['address_components'] ['1'] ['long_name'];
}
但是对于数组中更多数据的不同地址，例如：
http：//maps.googleapis .com / maps / api / geocode / json？latlng = 52.154184,6.199592& sensor = true
它不起作用，因为json数组中有更多的数据，并且它使省国家。
如何选择我需要的类型（long_name）？
$ b
- for street：long_name其中types：[route]
- long_name其中types：[locality，political]
- 适用于country：long_name其中types：[country，political]
地理编码JSON的输出示例：
{
结果：[
{
address_components：[
{
long_name：89，
short_name：89 ，
types：[street_number]
}，
{
long_name：Wieck De，
short_name：Wieck De ，
types：[establishment]
}，
{
long_name：Industrieweg，
short_name：Industrieweg，
types：[route]
}，
{
l ong_name：Zutphen，
short_name：Zutphen，
types：[locality，political]
}，
{
long_name：Zutphen，
short_name：Zutphen，
types：[administrative_area_level_2，political]
}，
{
long_name：Gelderland，
short_name：GE，
types：[administrative_area_level_1，political]
}，
{
long_name：Nederland，
short_name：NL，
types：[country，political]
}，
{
long_name：7202 CA，
short_name：7202 CA，
types：[postal_code]
}
我认为我自己修改了它，因此我的代码：
// street
foreach（$ jsondata [results] as $ result）{
foreach（$ result [ address_components]为$ address）{
if（in_array（route，$ address [types]））{
$ street = $ address [long_name];
}
}
}
// city
foreach（$ jsondata [results] as $ result）{
foreach（$ result [ address_components]为$ address）{
if（in_array（locality，$ address [types]））{
$ city = $ address [long_name];
}
}
}
// country
foreach（$ jsondata [results] as $ result）{
foreach（$ result [ address_components]为$ address）{
if（in_array（country，$ address [types]））{
$ country = $ address [long_name];
您可以将数据转换为关联数组并像它一样工作，如
$ data = array（）;
foreach（$ jsondata ['results'] ['0'] ['address_components'] as $ element）{
$ data [implode（''，$ element ['types']）] = $元件[ 'LONG_NAME'];
}
print_r（$ data）;
echo'route：'。 $ data ['route']。 \\\
;
echo'country：'。 $ data ['country political'];
I'm trying to getting the $street, $city and $country string from google json. It works for my home address : http://maps.googleapis.com/maps/api/geocode/json?latlng=52.108662,6.307370&sensor=true
$url = "http://maps.googleapis.com/maps/api/geocode/json?latlng=".$lat.",".$lng."&sensor=true";
$data = @file_get_contents($url);
$jsondata = json_decode($data,true);
if(is_array($jsondata) && $jsondata['status'] == "OK")
{
$city = $jsondata['results']['0']['address_components']['2']['long_name'];
$country = $jsondata['results']['0']['address_components']['5']['long_name'];
$street = $jsondata['results']['0']['address_components']['1']['long_name'];
}
But for a different address with more data in the arrays like this example: http://maps.googleapis.com/maps/api/geocode/json?latlng=52.154184,6.199592&sensor=true it doesn't work, because there is more data in the json array and it makes the province the country.
How can I select the type that I need (long_name)?
- for street : long_name where "types" : [ "route" ]
- for city : long_name where "types" : [ "locality", "political" ]
- for country : long_name where "types" : [ "country", "political" ]
Example output from the geocode JSON:
{
"results" : [
{
"address_components" : [
{
"long_name" : "89",
"short_name" : "89",
"types" : [ "street_number" ]
},
{
"long_name" : "Wieck De",
"short_name" : "Wieck De",
"types" : [ "establishment" ]
},
{
"long_name" : "Industrieweg",
"short_name" : "Industrieweg",
"types" : [ "route" ]
},
{
"long_name" : "Zutphen",
"short_name" : "Zutphen",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Zutphen",
"short_name" : "Zutphen",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Gelderland",
"short_name" : "GE",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "Nederland",
"short_name" : "NL",
"types" : [ "country", "political" ]
},
{
"long_name" : "7202 CA",
"short_name" : "7202 CA",
"types" : [ "postal_code" ]
}
I think I fixed it myself, hereby my code:
// street
foreach ($jsondata["results"] as $result) {
foreach ($result["address_components"] as $address) {
if (in_array("route", $address["types"])) {
$street = $address["long_name"];
}
}
}
// city
foreach ($jsondata["results"] as $result) {
foreach ($result["address_components"] as $address) {
if (in_array("locality", $address["types"])) {
$city = $address["long_name"];
}
}
}
// country
foreach ($jsondata["results"] as $result) {
foreach ($result["address_components"] as $address) {
if (in_array("country", $address["types"])) {
$country = $address["long_name"];
}
}
}
You could convert the data to the associative array and work with it like
$data = array();
foreach($jsondata['results']['0']['address_components'] as $element){
$data[ implode(' ',$element['types']) ] = $element['long_name'];
}
print_r($data);
echo 'route: ' . $data['route'] . "\n";
echo 'country: ' . $data['country political'];
这篇关于通过使用谷歌反向地理编码获得街道，城市和国家的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
