谷歌地图api v3如何按最近距离排名 [英] google maps api v3 how to rank by closest distance

问题描述

有谁知道如何使用这里提到的距离搜索选项排名？
https://developers.google.com/maps/documentation/javascript / places＃place_search_requests

在请求选项中列出此项似乎不起作用。这是我的部分代码：

pre $ var $ request $ {
location：coords，
/ / radius：30000，
关键字：['puma，retail']，
类型：['store']，
rankBy：google.maps.places.RankBy.DISTANCE
};

service = new google.maps.places.PlacesService（map）;
service.search（request，callback）;

函数回调（结果，状态）{
if（status == google.maps.places.PlacesServiceStatus.OK）{
for（var i = 0; i< results.length; i ++）{
createMarker（results [i]）;
listResults（results [i]）;
}
}
}

代码将定位并列出结果如果我包含半径，但结果未按距离按升序排列。 Google的文档说如果使用rankBy选项，则不需要半径。我错过了什么？

解决方案

遇到同样的问题。
根据此来源： http://www.geocodezip.com/v3_GoogleEx_place-search。 html
我能够制定这样的查询：

  var request = {
位置：gps，
类型：['food']，//您也可以在此替换关键字：'食物'，（不含双引号）。 
 rankBy：google.maps.places.RankBy.DISTANCE，//注意这里没有引号，我犯了这个错误。 
 key：key 
}; 
  

Var key是API密钥，它不是必需的，但会添加以备后用。 GPS是：

  var gps = new google.maps.LatLng（location.lat，location.lon）; 
  

最后，我做了您所做的一切，只是我添加了一个地图的界限，而我不打算使用。为此，我做了：

  var bounds = new google.maps.LatLngBounds（）; 
  

Does anyone know how to use the rank by distance search option that is mentioned here? https://developers.google.com/maps/documentation/javascript/places#place_search_requests

Listing this in the request options doesn't seem to work. Here's my portion of code relative to this:

var request = {
  location: coords,
  //radius: 30000,
  keyword: ['puma, retail'],
  types: ['store'],
  rankBy: google.maps.places.RankBy.DISTANCE
};

service = new google.maps.places.PlacesService(map);
service.search(request, callback);

function callback(results, status) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {
        for (var i = 0; i < results.length; i++) {
            createMarker(results[i]);
                            listResults(results[i]);
        }
    } 
}

Code will locate and list results if I include a radius, but the results aren't listed in ascending order by distance. Google's docs say a radius isn't necessary either if using the rankBy option. Am I missing something?

解决方案

Was having the same problem. As per this source: http://www.geocodezip.com/v3_GoogleEx_place-search.html I was able to formulate the query as such:

var request = {
location: gps,
types: ['food'], //You can substitute "keyword: 'food'," (without double-quotes) here as well.
rankBy: google.maps.places.RankBy.DISTANCE, //Note there is no quotes here, I made that mistake.
key: key 
};

Var key is API key which is not required but added for later use. GPS is:

var gps = new google.maps.LatLng(location.lat,location.lon);

Lastly, I did everything that you did except I added bounds to a map that I was not going to use. For that I did:

var bounds = new google.maps.LatLngBounds();

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