从用户位置查找最接近的经度和纬度 - iOS Swift [英] Find closest longitude and latitude in array from user location - iOS Swift

问题描述

在问题发布这里，用户问：

我有一个阵列充满了经度和纬度。我有两个双重变量与我的用户位置。我想测试我的用户位置与阵列之间的距离，以查看哪个位置最接近。我如何做到这一点？

这将得到2个位置之间的距离，但是拼命地理解我将如何对阵一系列位置进行测试。 b $ b

作为回应，他得到了以下代码：

  NSArray * locations = //您的CLLocation对象数组
 CLLocation * currentLocation = //当前设备位置
 
 CLLocation * closestLocation; 
 CLLocationDistance smallestDistance = DBL_MAX; //设置最大值
 
（CLLocation * location in location）{
 CLLocationDistance distance = [currentLocation distanceFromLocation：location]; 
 
 if（distance< smallestDistance）{
 smallestDistance = distance; 
 closestLocation = location; 
} 
} 
 NSLog（@smallestDistance =％f，smallestDistance）; 
  

在我正在处理的应用程序中，我有完全相同的问题，我认为这块代码可以完美工作。但是，我正在使用Swift，并且此代码位于Objective-C中。

我唯一的问题是：它应该在Swift中看起来如何？

感谢您的帮助。我对这一切都很陌生，在Swift中看到这段代码可能是一个大问题。

  var closestLocation：CLLocation？ 
 var smallestDistance：CLLocationDistance？ 
 
位置位置{
 let distance = currentLocation.distanceFromLocation（位置）
如果smallestDistance == nil ||距离< smallestDistance {
 closestLocation = location 
 smallestDistance = distance 
} 
} 
 
 print（smallestDistance = \（smallestDistance））
  

或作为函数：

  func locationInLocations（位置：[CLLocation]，closestToLocation位置：CLLocation） - > CLLocation？ {
如果locations.count == 0 {
返回nil 
} 
 
 var closestLocation：CLLocation？ 
 var smallestDistance：CLLocationDistance？ 
 
位置位置{
 let distance = location.distanceFromLocation（位置）
如果smallestDistance == nil ||距离< smallestDistance {
 closestLocation = location 
 smallestDistance = distance 
} 
} 
 
 print（closestLocation：\（closestLocation），distance：\（最小距离））
返回最近位置
} 
  

In the question posted here, the user asked:

I have an array full of longitudes and latitudes. I have two double variables with my users location. I'd like to test the distance between my user's locations against my array to see which location is the closest. How do I do this?

This will get the distance between 2 location but stuggeling to understand how I'd test it against an array of locations.

In response, he got the following code:

NSArray *locations = //your array of CLLocation objects
CLLocation *currentLocation = //current device Location

CLLocation *closestLocation;
CLLocationDistance smallestDistance = DBL_MAX; // set the max value

for (CLLocation *location in locations) {
    CLLocationDistance distance = [currentLocation  distanceFromLocation:location];

    if (distance < smallestDistance) {
        smallestDistance = distance;
        closestLocation = location;
    }
}
NSLog(@"smallestDistance = %f", smallestDistance);

I have the exact same problem in an application I'm working on, and I think this piece of code could work perfectly. However, I'm using Swift, and this code is in Objective-C.

My only question is: how should it look in Swift?

Thanks for any help. I'm new to all of this, and seeing this piece of code in Swift could be a big leg up.

解决方案

var closestLocation: CLLocation?
var smallestDistance: CLLocationDistance?

for location in locations {
  let distance = currentLocation.distanceFromLocation(location)
  if smallestDistance == nil || distance < smallestDistance {
    closestLocation = location
    smallestDistance = distance
  }
}

print("smallestDistance = \(smallestDistance)")

or as a function:

func locationInLocations(locations: [CLLocation], closestToLocation location: CLLocation) -> CLLocation? {
  if locations.count == 0 {
    return nil
  }

  var closestLocation: CLLocation?
  var smallestDistance: CLLocationDistance?

  for location in locations {
    let distance = location.distanceFromLocation(location)
    if smallestDistance == nil || distance < smallestDistance {
      closestLocation = location
      smallestDistance = distance
    }
  }

  print("closestLocation: \(closestLocation), distance: \(smallestDistance)")
  return closestLocation
}

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