使用非英文字符的Google http://maps.google.com/maps/geo查询 [英] Google http://maps.google.com/maps/geo query with non-english characters

问题描述

我正在创建一个Python语言（使用 urllib2 ）解析其中包含非英文字符的地址。我们的目标是找到每个地址的坐标。

当我在 Firefox 中打开此网址时：

  http://maps.google.com/maps/geo?q=Czech%20Republic%2010000%20Male%C5%A1ice&output=csv 
  

将它转换（地址栏中的更改）为

  http://maps.google.com/maps/geo?q=Czech Republic 10000Malešice& output = csv 
  

和退货

  200,6,50.0865113,14.4918052 
 
 code> 

这是正确的结果。



然而，如果我在 urllib2 （或Opera浏览器）中打开相同的URL（用％20等编码），结果为

  200,4,49.7715220,13.2955410 
  

不正确。如何打开 urllib2 中的第一个网址以获得 200,6,50.0865113,14.4918052 结果？



编辑：



使用的代码



 导入urllib2 
 
 psc ='10000'
 name ='Malešice'
 url ='http：//地图.google.com / maps / geo？q =％s& output = csv'％urllib2.quote（'Czech Republic％s％s'％（psc，name））
 
 response = urllib2。 urlopen（url）
 data = response.read（）
 
 print'Parsed url％s，result％s\\\
'％（url，data）
  

输出



解析网址http：// maps.google.com/maps/geo?q=Czech%20Republic%2010000%20Male%C5%A1ice&output=csv，结果200,4,47,72,220,13,2955410

$ b $我可以重现这种行为，起初我对它为何发生了傻眼。使用 wireshark 进一步检查HTTP请求表明，Firefox发送的请求（不奇怪）包含更多的HTTP - 头部。

最终结果是 Accept-Language 标头这是有所不同的。如果

• 和 Accept-Language 标头设置为


• 和它首先列出非英语语言（优先级似乎不重要）

所以，例如这个 Accept-Language 头文件：

<$ p $
$> $ $ $ $ $ $ $ $ $ $总之，像这样修改你的代码适合我：

 ＃ -  *  -  coding：utf-8  - *  -  
导入urllib2 
 
 psc ='10000'
 name ='Malešice'
 url ='http://maps.google.com/maps/geo ？q =％s& output = csv'％urllib2.quote（'Czech Republic％s％s'％（psc，name））
 headers = {'Accept-Language'：'de-ch，en' } 
 
 req = urllib2.Request（url，None，headers）
 response = urllib2.urlopen（req）
 data = response.read（）
 
 print'Parsed url％s，result％s\\\
'％（url，data）
  

注意：在我看来，这是Google地理编码API中的一个错误。 Accept-Language 标题指示用户代理偏好哪些语言的内容，但它不应该影响请求被解释的方式。

I'm creating a Python (using urllib2) parser of addresses with non-english characters in it. The goal is to find coordinates of every address.

When I open this url in Firefox:

http://maps.google.com/maps/geo?q=Czech%20Republic%2010000%20Male%C5%A1ice&output=csv

it is converted (changes in address box) to

http://maps.google.com/maps/geo?q=Czech Republic 10000 Malešice&output=csv

and returns

200,6,50.0865113,14.4918052

which is a correct result.

However, if I open the same url (encoded, with %20 and such) in urllib2 (or Opera browser), the result is

200,4,49.7715220,13.2955410

which is incorrect. How can I open the first url in urllib2 to get the "200,6,50.0865113,14.4918052" result?

Edit:

Code used

import urllib2

psc = '10000'
name = 'Malešice'
url = 'http://maps.google.com/maps/geo?q=%s&output=csv' % urllib2.quote('Czech Republic %s %s' % (psc, name))

response = urllib2.urlopen(url)
data = response.read()

print 'Parsed url %s, result %s\n' % (url, data)

output

Parsed url http://maps.google.com/maps/geo?q=Czech%20Republic%2010000%20Male%C5%A1ice&output=csv, result 200,4,49.7715220,13.2955410

解决方案

I can reproduce this behavior, and at first I was dumbfounded as to why it's happening. Closer inspection of the HTTP requests with wireshark showed that the requests sent by Firefox (not surprisingly) contain a couple more HTTP-Headers.

In the end it turned out it's the Accept-Language header that makes the difference. You only get the correct result if

• an Accept-Language header is set
• and it has a non-english language listed first (the priorities don't seem to matter)

So, for example this Accept-Language header works:

headers = {'Accept-Language': 'de-ch,en'}

To summarize, modified like this your code works for me:

# -*- coding: utf-8 -*-
import urllib2

psc = '10000'
name = 'Malešice'
url = 'http://maps.google.com/maps/geo?q=%s&output=csv' % urllib2.quote('Czech Republic %s %s' % (psc, name))
headers = {'Accept-Language': 'de-ch,en'}

req = urllib2.Request(url, None, headers)
response = urllib2.urlopen(req)
data = response.read()

print 'Parsed url %s, result %s\n' % (url, data)

Note: In my opinion, this is a bug in Google's geocoding API. The Accept-Language header indicates what languages the user agent prefers the content in, but it shouldn't have any effect on how the request is interpreted.

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