在python中迭代Geocoding API响应 [英] Iterating through Geocoding API response in python

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本文介绍了在python中迭代Geocoding API响应的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图在反向地理编码Google Maps API中找到 ['locality','political'] 值。



我可以在Javascript中实现如下功能:

  var formatted = data.results; 
$ .each(格式化,函数(){
if(this.types.length!= 0){
if(this.types [0] =='locality'&& amp ; this.types [1] =='political'){
address_array = this.formatted_address.split(',');
} else {
// somefunction
}
} else {
// somefunction
}
});

使用Python,我尝试了以下方法:

  url ='https://maps.googleapis.com/maps/api/geocode/json?latlng='+lat+','+long+'&result_type=locality&key ='+ MAPS_API_KEY 
results = json.loads(urllib.request.urlopen(url).read()。decode('utf-8'))
city_components = results ['results'] [0 ]
for c in results:
if c ['types']:
if c ['types'] [0] =='locality':
print(c [ 'types'])

这给我一堆错误。我无法绕过响应对象来查找 ['locality','political'] 值来查找相关City SHORT_NAME 。如何解决这个问题?

解决方案

您试图访问字典的键,但是您正在迭代该键的字符:

 结果中的c:
if c ['types']:

结果是一个字典(从 city_components = line)。当你在结果中键入 for c时,你将 c 绑定到该字典的键(依次)。这意味着 c 是一个字符串(在你的场景中,很可能所有的键都是字符串)。因此,然后键入 c ['types'] 没有意义:您正尝试访问值/属性'types'一个字符串...

最有可能你想要:

 在结果['results']中选择:
addr_comp = option.get('address_components',[])
用于addr_comp中的address_type:
flags = address_type.get('types ',[])
如果标志中的'locality'和标志中的'political':
print(address_type ['short_name'])


I'm trying to find the ['locality', 'political'] value in the reverse geocoding Google Maps API.

I could achieve the same in Javascript as follows:

var formatted = data.results;
$.each(formatted, function(){
     if(this.types.length!=0){
          if(this.types[0]=='locality' && this.types[1]=='political'){
               address_array = this.formatted_address.split(',');
          }else{
               //somefunction
          }
     }else{
         //somefunction
     }
});

Using Python, I tried the following:

url = 'https://maps.googleapis.com/maps/api/geocode/json?latlng='+lat+','+long+'&result_type=locality&key='+MAPS_API_KEY
results = json.loads(urllib.request.urlopen(url).read().decode('utf-8'))
city_components = results['results'][0]
for c in results:
    if c['types']:
        if c['types'][0] == 'locality':
            print(c['types'])

This gives me a bunch of errors. I'm not able to get my head around iterating through the response object to find the ['locality', 'political'] value to find the related City short_name. How do I go about solving this?

解决方案

You are trying to access the keys of a dictionary, but instead you are iterating over the characters of that key:

for c in results:
    if c['types']:

results is a dictionary (obvious from your city_components= line). When you type for c in results, you are binding c to the keys of that dictionary (in turn). That means c is a string (in your scenario, most likely all the keys are strings). So then typing c['types'] does not make sense: you are trying to access the value/attribute 'types' of a string...

Most likely you wanted:

for option in results['results']:
    addr_comp = option.get('address_components', [])
    for address_type in addr_comp:
        flags = address_type.get('types', [])
        if 'locality' in flags and 'political' in flags:
            print(address_type['short_name'])

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