插入php代码后地图页面变为空白 [英] map page becomes blank after inserting php code

问题描述

在将php代码插入infowindow内容后，我的gmap页面变为空白。

  google.maps.event.addListener（noi ，'mouseover'，function（）{
 var infowindow = new google.maps.InfoWindow（{
 content：'<？php 
 if（$ count == 0）{
 echoNo Open Tickets; 
} 
 else {
 echo< table>; 
 foreach（$ NOIcompliancearray as $ SLA_Compliance => $ count）{ 
 $ Npath = $ Nimages [$ SLA_Compliance]; 
 echo< tr>; 
 echo< td>< a href ='city.php？city = Noida& $ SLA_Compliance。'>< / td>; 
 echo< img src ='IndiaImages /\".$ Npath。'title ='。 < td>。$ count。< / td>; 
 echo< / tr>; 
} 
 echo< / table>; 
} 
？>'
 size：new google.maps.Size（100,100），
}）; 
 go ogle.maps.event.addListener（noi，'mouseover'，function（）{
 infowindow.open（map，noi）; 
 setTimeout（function（）{infowindow.close（map，noi）}，5000）; 
}）; 
  

如果我用一些静态内容替换php代码，它可以正常工作。另外，当我尝试打开网页源代码时，它给了我想要在信息窗口中看到的结果。我不知道我在哪里犯了错误。

从网页源代码输出：
内容：

 '< table>< tr>< td>< a href ='city.php？city = Noida& compliance = A'>< img src ='IndiaImages / Circle_Red.gif'title ='A'>< / td>< td> 3< / td>< / tr>< tr>< td>< a href ='city.php？city = Noida& compliance = C'>< img src ='IndiaImages / Circle_Yellow.gif'title ='C'>< / td>< td> 10< / td>< / tr>< / table> ; Noida' 

请帮助我理解错误并减轻问题。

解决方案

code> google.maps.event.addListener（noi，'mouseover'，function（）{
var infowindow = new google。 maps.InfoWindow（{
content：'...'
size：new google.maps.Size（100,100），
}）;

用php获得

  google.maps.event.addListener（noi，'mouseover'，function（）{
 var infowindow = new google.maps.InfoWindow（{
 content：'< table> ; 
< tr> 
< td>< a href ='
 //'city.php？city = ......'在内容之后：字符串结尾符号````会被函数忽略！
 size：new google.maps.Size（100,100），
}）; 
  

由 php 生成的第一个'将被解释为字符串的结尾
其余的将在html源代码中，你可以看到它，但被函数忽略。

所以不要使用'。

  echo< td>< a href ='city。 php？city = Noida& compliance =。$ SLA_Compliance。'> 
  

转义标志而不是

  echo< td>< a href = \\city.php？city = Noida& ompliance = \。$ SLA_Compliance。\>
  

转义 看看这里

My gmap page turns blank after inserting php code into the infowindow content.

google.maps.event.addListener(noi, 'mouseover', function() {
  var infowindow = new google.maps.InfoWindow({
    content: '<?php 
        if ($count==0){
        echo "No Open Tickets";
        }
    else{
        echo "<table>";
        foreach ($NOIcompliancearray as $SLA_Compliance=>$count) {
            $Npath = $Nimages[$SLA_Compliance];
            echo "<tr>";
            echo "<td><a href='city.php?city=Noida&compliance=".$SLA_Compliance."'><img src='IndiaImages/".$Npath."' title='".$SLA_Compliance."' ></td>";
            echo "<td>".$count."</td>";
            echo "</tr>";
            }
        echo "</table>";        
    }
  ?>'
    size: new google.maps.Size(100,100),
  });
google.maps.event.addListener(noi, 'mouseover', function() {
infowindow.open(map,noi);
setTimeout(function() { infowindow.close(map, noi) }, 5000);
});

If i replace php code with some static content it works fine. Also, when I tried opening the webpage source code, it gives me result which i wanted to see in the info window. I am not sure where I am making mistake.

output from the webpage source code: content:

'<table><tr><td><a href='city.php?city=Noida&compliance=A'><img src='IndiaImages/Circle_Red.gif' title='A' ></td><td>3</td></tr><tr><td><a href='city.php?city=Noida&compliance=C'><img src='IndiaImages/Circle_Yellow.gif' title='C' ></td><td>10</td></tr></table>Noida'

Kindly help me understand the mistake and to mitigate the problem.

解决方案

Look at the function

google.maps.event.addListener(noi, 'mouseover', function() {
  var infowindow = new google.maps.InfoWindow({
    content: '...'
    size: new google.maps.Size(100,100),
  });

with php you get

google.maps.event.addListener(noi, 'mouseover', function() {
  var infowindow = new google.maps.InfoWindow({
    content: '<table>
            <tr>
            <td><a href='
   // 'city.php?city=......' is after content : string ending sign `'` will be ignored by function !
    size: new google.maps.Size(100,100),
  });

The first ' generated by php will interpreted as end of the string the rest will be in html source. you can see it but ignored by the function.

So don't use ' in that kind of code.

echo "<td><a href='city.php?city=Noida&compliance=".$SLA_Compliance."'>

escape the " sign instead

echo "<td><a href=\"city.php?city=Noida&ompliance=\"".$SLA_Compliance."\">"

escape " look here

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