编程意见如何设置唯一的ID？ [英] Programmatic Views how to set unique id's?

问题描述

我创建我的应用程序一堆纲领性查看秒。因为它似乎是他们都在默认情况下具有相同的 ID = -1 。为了与他们合作，我需要生成唯一的ID。

I am creating in my app bunch of programmatic Views. As it appeared to be they all by default have the same id=-1. In order to work with them I need to generate unique id's.

我尝试了好几种方法 - 随机数的产生，并根据当前时间，但无论如何也没有100％的保证不同的看法会有不同的ID的

I have tried several approaches - random number generation and based on current time, but anyway there's no 100% guarantee that different Views will have different id's

只是想知道有没有更可靠的方式来生成唯一的吗？也许有特殊的方法/类？

Just wondering is there any more reliable way to generate unique ones? Probably there's special method/class?

推荐答案

创建一个单独的类，有一个原子整数。凹凸的整数，当你需要一个视图id返回值。

Create a singleton class, that has an atomic Integer. Bump the integer, and return the value when you need a view id.

该ID将成为您流程的执行过程中唯一的，但西港岛线复位时，你的进程将重新启动。

The id will be unique during the execution of your process, but wil reset when your process is restarted.

public class ViewId {

    private static ViewId INSTANCE = new ViewId();

    private AtomicInteger seq;

    private ViewId() {
        seq = new AtomicInteger(0);
    }

    public int getUniqueId() {
        return seq.incrementAndGet();
    }

    public static ViewId getInstance() {
        return INSTANCE;
    }
}

请注意，该ID可能不是唯一的，如果已经是具有IDS在视图'图'的看法。您可以尝试以数字开头即是Integer.MAX_VALUE，并减少而不是从1去它 - > MAX_VALUE

Note that the id might not be unique, if there already are views that have ids in the view 'graph'. You could try to start with a number that is Integer.MAX_VALUE, and decrease it instead of going from 1 -> MAX_VALUE

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