为特定的风格和buildType定义buildconfigfield [英] Define buildconfigfield for an specific flavor AND buildType

问题描述

我有两种口味，可以说是香草和巧克力。我也有Debug和Release构建类型，并且我需要Vanilla Release有一个字段为true，而其他3个组合应该是false。

  def BOOLEAN =boolean
 def VARIABLE =VARIABLE
 def TRUE =true
 def FALSE =false
 
 VANILLA {
 
 debug {
 
 buildConfigField BOOLEAN，VARIABLE，FALSE 
 
} 
 
 release {
 
 buildConfigField BOOLEAN，VARIABLE，TRUE 
 
} 
 
 
} 
 
巧克力{
 buildConfigField BOOLEAN，VARIABLE，FALSE 
 
  

我有一个错误，所以我想调试和发布技巧不起作用。可以这样做吗？

解决方案

循环变体并检查它们的名称：

  productFlavors {
 vanilla {} 
巧克力{} 
} 
 
 applicationVariants.all {variant  - > ; 
 println（Iterating variant：+ variant.getName（））
 if（variant.getName（）==chocolateDebug）{
 variant.buildConfigFieldboolean，VARIABLE ，true
} else {
 variant.buildConfigFieldboolean，VARIABLE，false
} 
} 
  

I have 2 flavors, lets say Vanilla and Chocolate. I also have Debug and Release build types, and I need Vanilla Release to have a field true, while the other 3 combinations should be false.

def BOOLEAN = "boolean"
def VARIABLE = "VARIABLE"
def TRUE = "true"
def FALSE = "false"

    VANILLA {

        debug {

            buildConfigField BOOLEAN, VARIABLE, FALSE

        }

        release {

            buildConfigField BOOLEAN, VARIABLE, TRUE

        }


    }

    CHOCOLATE {
        buildConfigField BOOLEAN, VARIABLE, FALSE
    }

I'm having an error, so I guess the debug and release trick doesnt work. It is possible to do this?

解决方案

Loop the variants and check their names:

productFlavors {
    vanilla {}
    chocolate {}
}

applicationVariants.all { variant ->
    println("Iterating variant: " + variant.getName())
    if (variant.getName() == "chocolateDebug") {
        variant.buildConfigField "boolean", "VARIABLE", "true"
    } else {
        variant.buildConfigField "boolean", "VARIABLE", "false"
    }
}

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