获得从联系人列表Android的唯一的电子邮件地址 [英] Get only email address from contact list Android

问题描述

我想只显示那些联系人姓名的电子邮件地址是present。否则，该联系人名称不应该显示在列表中。我怎样才能做到这一点？任何人都可以请帮我吗？

解决方案

 公开的ArrayList＆LT;字符串＆GT; getNameEmailDetails（）{
        ArrayList的＆LT;字符串＆GT;名称=新的ArrayList＆LT;字符串＆GT;（）;
        ContentResolver的CR = getContentResolver（）;
        光标CUR = cr.query（ContactsContract.Contacts.CONTENT_URI，NULL，NULL，NULL，NULL）;
        如果（cur.getCount（）大于0）{
            而（cur.moveToNext（））{
                字符串ID = cur.getString（cur.getColumnIndex（ContactsContract.Contacts._ID））;
                光标CUR1 = cr.query（
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI，空，
                        ContactsContract.CommonDataKinds.Email.CONTACT_ID +=？，
                                新的String [] {ID}，NULL）;
                而（cur1.moveToNext（））{
                    //获取联系人姓名
                    字符串名称= cur1.getString（cur1.getColumnIndex（ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME））;
                    Log.e（姓名：，姓名）;
                    字符串email = cur1.getString（cur1.getColumnIndex（ContactsContract.CommonDataKinds.Email.DATA））;
                    Log.e（电子邮件，电子邮件）;
                    如果（电子邮件！= NULL）{
                        names.add（名称）;
                    }
                }
                cur1.close（）;
            }
        }
        返回名称;
    }
 

以上方法返回的名字里面有电子邮件ID的ArrayList

I want to display only those contact names whose email address is present. Otherwise that contact name should not be displayed in List. How can I do this? Can anybody please help me?

解决方案

public ArrayList<String> getNameEmailDetails(){
        ArrayList<String> names = new ArrayList<String>();
        ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                Cursor cur1 = cr.query( 
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
                        ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", 
                                new String[]{id}, null); 
                while (cur1.moveToNext()) { 
                    //to get the contact names
                    String name=cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    Log.e("Name :", name);
                    String email = cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                    Log.e("Email", email);
                    if(email!=null){
                        names.add(name);
                    }
                } 
                cur1.close();
            }
        }
        return names;
    }

the above method return an arraylist of names which has email id.

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