通过将根设置为localhost:8080 /而不是localhost:8080 / app或修改createLink的Intelli-J启动grails-app? [英] Launching a grails-app through Intelli-J with root set to localhost:8080/ instead of localhost:8080/app, or modifying createLink?
问题描述
有没有办法通过Intelli-J启动应用程序,以便使应用程序的根目录为 localhost:8080 /
?我遇到的问题是,在本地工作的AJAX网址在生产中不起作用,并且 createLink(action:ajaxUpdate)
似乎创建对<$ c>的引用
有没有办法解决 / app / ajaxUpdate
,它在本地工作, createLink 在两个位置工作?我想也许我可以使用UrlMappings来完成所有的ajax调用,并引用 / ajaxUpdate
,但这不起作用,因为grails应用程序是如何部署的Intelli-J。
我该如何解决这个问题?
关于您的问题,您可以在 grails-app / conf / Config.groovy 中指定服务器URL,如下所示:
environments {
production {
grails.serverURL =http:// localhost ///指定链接的根
... 。
}
development {
grails.serverURL =http:// localhost:8080 / $ {appName}
...
}
...
}
然后createLink方法应该没问题。据我所知,这是关于Grails配置,与IntelliJ无关。
编辑:似乎我错过了一些信息:使createLink在http://开始 grails.app.context =/$ blocalhost /,则需要在Config.groovy中添加另一行。 $ b
Is there a way to launch an application through Intelli-J so that it makes localhost:8080/
the root of the application? The problem I'm having is that AJAX urls that work locally don't work in production, and createLink(action:"ajaxUpdate")
seems to create references to /app/ajaxUpdate
, which works locally but not in production.
Is there a way to fix createLink
to work in both locations? I thought perhaps I could just use UrlMappings to make all the ajax calls pretty and just refer to /ajaxUpdate
, but that doesn't work because of how the grails application is deployed within Intelli-J.
How do I fix this?
About your problem, in grails-app/conf/Config.groovy you can specify the server URL, like this:
environments {
production {
grails.serverURL = "http://localhost/" // Specify the "root" of your link
....
}
development {
grails.serverURL = "http://localhost:8080/${appName}"
...
}
...
}
Then the createLink method should be fine. As I know, it's about Grails config, not relate to IntelliJ.
EDIT: It seems that I missed some information: to make the createLink start at "http://localhost/", it's necessary to add another line into Config.groovy:
grails.app.context = "/"
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