Grails：我如何在Grails过滤器中设置响应包装？ [英] Grails: how do I set up a response wrapper in a Grails filter?

问题描述

我想修改特定Grails请求的响应内容。如何在请求过滤器中配置ResponseWrapper？

我曾希望它是以下内容，但响应是只读属性：

  class MyFilters {
 def filters = {
 wrapFoo（controller：'foo'，action：'bar'）{
 before = {
 response = new MyResponseWrapper（response）
} 
 [...] 
  

谢谢！

解决方案

您无法 - Grails过滤器是Spring HandlerInterceptors的包装器，在servlet过滤器之上被进一步调用处理链。如果你想打包响应，你需要使用一个真正的servlet过滤器。

在src / java或src / groovy中创建实现 javax.servlet.Filter 并将其注册到web.xml中，就像在非Grails应用程序中一样。要访问web.xml，运行 grails install-templates ，然后编辑src / templates / war中的文件

I want to modify the response content of specific Grails requests. How do I configure a ResponseWrapper in a request filter?

I had hoped it would be the following, but the response is a read-only property:

class MyFilters {
    def filters = {
        wrapFoo(controller:'foo', action:'bar') {
            before = {
                response = new MyResponseWrapper(response)
            }
        [...]

Thanks!

解决方案

You can't - Grails filters are wrappers for Spring HandlerInterceptors and are invoked further up the processing chain than servlet filters. If you want to wrap the response you need to use a real servlet filter.

Create the class in src/java or src/groovy that implements javax.servlet.Filter and register it in web.xml like you would in a non-Grails application. To get access to web.xml run grails install-templates and edit the file in src/templates/war

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