使用AffineTransform将形状缩放/转换为给定的矩形 [英] Scaling/Translating a Shape to a given Rectangle using AffineTransform

问题描述

我试图用 AffineTransform 缩放/转换一个java.awt。 Shape ，以便将其绘制到定义的边界矩形中。

此外，我想在绘制具有' zoom '参数的区域中绘制它。

I尝试了AffineTransform的各种连接，但我找不到正确的序列。例如，下面的解决方案是错误的：

  double zoom =（...）; / *当前缩放* / 
 Rectangle2D viewRect =（...）/ **我们想要绘制形状的矩形* / 
形状=（...）/ *应该放在矩形中的原始形状viewRect * / 
 Rectangle2D bounds = shape.getBounds2D（）; 
 
 double ratioW =（viewRect.getWidth（）/ bounds.getWidth（））; 
 double ratioH =（viewRect.getHeight（）/ bounds.getHeight（））; 
 
 
 AffineTransform转换[] = 
 {
 AffineTransform.getScaleInstance（zoom，zoom），
 AffineTransform.getTranslateInstance（-bounds.getX（）， （），
 AffineTransform.getTranslateInstance（viewRect.getX（），viewRect.getY（）），
 AffineTransform.getScaleInstance（ratioW，ratioH）
}; 
 
 
 AffineTransform tr = new AffineTransform（）; 
 for（int i = 0; i< transforms.length; ++ i）
 {
 tr.concatenate（transforms [i]）; 
} 
 
 Shape shape2 = tr.createTransformedShape（shape）; 
 graphics2D.draw（shape2）; 
  

关于正确的AffineTransform的任何想法？

非常感谢

Pierre

解决方案

请注意 AffineTransform 转换是以最常用的方式连接在一起的，这可能被认为是， first-out 顺序。可以在此示例中看到效果。根据下面的顺序，结果 Shape 首先被旋转，然后被缩放并最终被翻译。

  at.translate（SIZE / 2，SIZE / 2）; 
 at.scale（60，60）; 
 at.rotate（Math.PI / 4）; 
 return at.createTransformedShape（...）; 
  

I'm trying to scale/translate a java.awt.Shape with AffineTransform in order to draw it in a defined bounding Rectangle.

Moreover, I want to paint it in a drawing Area having a 'zoom' parameter.

I tried various concatenations of AffineTransform but I couldn't find the correct sequence. For example, the following solution was wrong:

double zoom=(...);/* current zoom */
Rectangle2D viewRect=(...)/** the rectangle where we want to paint the shape */
Shape shape=(...)/* the original shape that should fit in the rectangle viewRect */
Rectangle2D bounds=shape.getBounds2D();

double ratioW=(viewRect.getWidth()/bounds.getWidth());
double ratioH=(viewRect.getHeight()/bounds.getHeight());


AffineTransform transforms[]=
    {
    AffineTransform.getScaleInstance(zoom, zoom),
    AffineTransform.getTranslateInstance(-bounds.getX(),-bounds.getY()),
    AffineTransform.getTranslateInstance(viewRect.getX(),viewRect.getY()),
    AffineTransform.getScaleInstance(ratioW, ratioH)
    };


AffineTransform tr=new AffineTransform();
for(int i=0;i< transforms.length;++i)
    {
    tr.concatenate(transforms[i]);
    }

Shape shape2=tr.createTransformedShape(shape);
graphics2D.draw(shape2);

Any idea about the correct AffineTransform ?

Many thanks

Pierre

解决方案

Note that AffineTransform transformations are concatenated "in the most commonly useful way", which may be regarded as last in, first-out order. The effect can be seen in this example. Given the sequence below, the resulting Shape is first rotated, then scaled and finally translated.

at.translate(SIZE/2, SIZE/2);
at.scale(60, 60);
at.rotate(Math.PI/4);
return at.createTransformedShape(...);

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