Java垃圾收集和图形处理方法 [英] Java Garbage Collection and Graphics dispose method

问题描述

我正在创建一款游戏（一个Snake Clone）作为一种爱好。我正在Java API的Graphics类中查看dispose方法。当我注释掉处理方法时，我的动画在有或没有它的情况下都可以正常工作。在Java API中，dispose方法执行此操作 - 释放图形上下文正在使用的系统资源。 Java垃圾收集不管理程序的内存类似于处理的内容吗？我应该保留处置方法吗？

API在解释同步方法方面没有太多帮助。但从我在其他论坛读到的内容来看，ToolKit类中的同步方法是为了确保绘图操作（如paintComponent方法，我猜想）会刷新显卡。所以，显卡的工作是清理程序以前的图形上下文的任何遗留物？

以下是代码：

  public void paintComponent（Graphics g）{
 super.paintComponent（g）; 
 Toolkit.getDefaultToolkit（）。sync（）; 
 g.dispose（）; 
 
 
  

解决方案

来到 Graphics 有一个简单的原则。

如果您明确地创建它（例如 BuffereImage.createGraphics（）），则将其处理掉。
$ b $ < paintComponent（Graphics g）实例 g 由工具包提供，并在需要时处理。在你自己的代码中这样做会导致'不可预知的'呈现。

I am creating a game (a Snake Clone) as a hobby. I was looking at the dispose method from the Graphics class in the Java API. When I comment out the dispose method, My animation works the same way just fine with or without it. In the Java API, the dispose method does this- releases system resources that the graphics context is using. Doesn't the Java garbage collection manage the memory of the program similar to what the dispose is doing? Should I keep the dispose method?

The API was not much help in explaining the sync method. But from what I read in other forums , the sync method from the ToolKit class is to ensure the drawing operation (like paintComponent method I suppose) flushes to the graphics card. So is the graphic card's job to clean up any remains of the previous graphics contexts of the program?

Here's the code:

 public void paintComponent(Graphics g) {
            super.paintComponent(g);
            Toolkit.getDefaultToolkit().sync();
            g.dispose();

     }

解决方案

When it comes to Graphics there is a simple principle.

If you explicitly create it (e.g. BuffereImage.createGraphics()) then dispose of it.

OTOH in paintComponent(Graphics g) the instance g is provided by the toolkit and disposed of when/if it needs to be. Doing so in your own code will cause 'unpredictable' rendering.

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