在grep / ack中转义括号 [英] Escaping a parenthesis in grep/ack

问题描述

我想查找字符串methodname（，但我无法转义（。我怎么能得到

  grep methodname（* 
  

或

  ack-grep methodname（* 
  

解决方案有两件事解释（：shell和 ack-grep 。

您可以使用''， 或 \ 将（ shell，例如

  grep'methodname（'* 
 grepmethodname（* 
 grep methodname \（* 
  

grep 正则表达式语言默认情况下是这样的，所以（不是特殊的。（如果你使用 egrep 或 grep -E 或 grep -P 。）

另一方面， ack-grep 以Perl正则表达式作为输入，其中（也是特殊的，因此您也必须将其转义。

  ack-grep'methodname \（'* 
 ack-grepmethodname \\（* 
 ack-grep methodname \\\（* 
 ack-grep'methodname [（]'* 
 ack-grepmethodname [（]* 
 ack-grep methodname \ [\（\] * 
  

I want to look for the string "methodname(", but I am unable to escape the "(". How can I get

grep methodname( *

or

ack-grep methodname( *

to work?

解决方案

There's two things interpreting the (: the shell, and ack-grep.

You can use '', "", or \ to escape the ( from the shell, e.g.

grep 'methodname(' *
grep "methodname(" *
grep methodname\( *

grep uses a basic regular expression language by default, so ( isn't special. (It would be if you used egrep or grep -E or grep -P.)

On the other hand, ack-grep takes Perl regular expressions as input, in which ( is also special, so you'll have to escape that too.

ack-grep 'methodname\(' *
ack-grep "methodname\\(" *
ack-grep methodname\\\( *
ack-grep 'methodname[(]' *
ack-grep "methodname[(]" *
ack-grep methodname\[\(\] *

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